Answer:
Explanation:
2 H₂S(g) +S0₂(g) = 3 S(s) + 2H₂0(g)
2 x 34 g 64 g 3 x 32 g
68 g of H₂S reacts with 64 g of S0₂
3.89 g of H₂S reacts with 64 x 3 .89 / 68 g of S0₂
3.89 g of H₂S reacts with 3.66 g of S0₂
S0₂ given is 4.11 g , so it is in excess .
Hence H₂S is limiting reagent .
68 g of H₂S reacts with S0₂ to give 96 g of Sulphur
3.89 g of H₂S reacts with S0₂ to give 96 x 3.89 / 68 g of Sulphur
3.89 g of H₂S reacts with S0₂ to give 96 x 3.89 / 68 g of Sulphur
5.49 g of Sulphur is produced .
Actual yield is 4.89
percentage yield = 4.89 x 100 / 5.49
= 89 % .
During ethyl alcohol fermentation<span>, the pyruvate molecules are broken down into ethyl </span>alcohol<span> molecules and carbon dioxide molecules. During </span>lactic<span> acid</span>fermentation<span>, the pyruvate molecules are broken down into </span>lactic<span> acid molecules only.</span>
Answer:
molecular formula = MgSO4.7H2O
Name is Magnesium sulfate heptahydrate
Explanation:
A hydrate of magnesium sulfate has a mass of 13.52 g. This sample is heated until no water remains. The MgSO4 anhydrate has a mass of 6.60 g. Find the formula and name of the hydrate.
given
mass 1 = 13.52 g
mass 2 = 6.60 g
solution
MgSO4 × H2O
first we ge here mass of hydrate part that is here
mass of hydrate part = (13.52 g - 6.60 g)
mass of hydrate part = 6.92 g
and
now we get here percentage of hydrate that is
percentage of hydrate = (6.92 / 13.52) x 100
percentage of hydrate = 51.18 %
so molar mass will be
molar mass of hydrate MgSO4 = 120.366 g/mol = 49.82 %
and for 100% = 241.6 g
so
mass of H2O = 121.23 g
and
moles of H2O = 7
so we can say that molecular formula will be MgSO4.7H2O
and name is Magnesium sulfate heptahydrate
Just look at the name, it tells you the longest C chain. Ending with hexane means that the longest carbon chain is 6 C's long.
Answer:
A) As the phase changes occur, the freedom of motion of the particles increases.
Explanation:
As the phase changes occur, the freedom of motion of the particles increases.