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Nookie1986 [14]
2 years ago
14

PLEASE HELP!!!!!! NO LIKNKS!!!!!! What are the values of x and y?

Mathematics
1 answer:
Anuta_ua [19.1K]2 years ago
7 0

Step-by-step explanation:

By the geometric mean theorem,

12/9 = 9/x

-> x=81/12 = 27/4

Then by the Pythagorean theorem,

y=sqrt(9^2 + (27/4)^2), which you can probably calculate yourself.

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Find the value of x and the value of y.
Elan Coil [88]

Answer:

Step-by-step explanation:

According to the diagram ,

Hypotenuse = 10√3

Opposite = x

Adjacent = y

α = 60

Using SOHCAHTOA ,

Sin α = opp / hyp

Sin 60= x/10√3

√3/2= x/10√3

x = 15

Pythagoras theorem ;

Hypotenuse ^2 = Opposite ^2 +Adjacent ^2

10√3 ^2 = 15^2+ y^2

300 = 225 +y ^2

300 -225 = y^2

75 = y^2

y = √75y

y = 5√3

5 0
3 years ago
Simplify (8m² + 3m - 5) + (m² - 7m - 1)
Rus_ich [418]

Answer:

9m^2 - 4m - 6

Step-by-step explanation: hope this helps!

8 0
2 years ago
Find the distance between each pair of points.<br> 3) (6, -2), (8, -3)<br> 4) (7,-8), (-8, 2)
castortr0y [4]

Answer:

3) \sqrt{5}

4)5\sqrt{13}

Step-by-step explanation:

distance between two points:

d = \sqrt{(x_{2}-x_{1})^{2}+ (y_{2}-y_{1})^{2}}

we have:

3) (6, -2), (8, -3)

x_{1} = 6

y_{1} =-2

x_{2} = 8

y_{2} =-3

so we have:

d =\sqrt{(8-6)^{2}+ (-3-(-2))^{2}}\\\\d =\sqrt{(2)^{2}+ (-1)^{2}}\\\\d = \sqrt{4+ 1}\\\\d=\sqrt{5}

4) (7,-8), (-8, 2)

x_{1} = 7

y_{1} =-8

x_{2} =-8

y_{2} =2

d =\sqrt{(-8-7)^{2}+ (2-(-8))^{2}}\\\\d =\sqrt{(-15)^{2}+ (10)^{2}}\\\\d = \sqrt{225+ 100}\\\\d=\sqrt{325}\\\\d=5\sqrt{13}

3 0
3 years ago
The total bill for 4 people came out to be $48. They plan on leaving a $12 tip
Goryan [66]

Answer:$15 each

Step-by-step explanation:48+12=60

60/4 = 15

7 0
3 years ago
Read 2 more answers
Decide if each expression is equivalent to 2^6 or 4^4
11Alexandr11 [23.1K]

\huge\text{Hey there!}

\mathsf{2^6 = 2\times2\times2\times2\times2\times2}\\\mathsf{2\times2\times2\times2\times2\times2}\\\mathsf{2\times2=4}\\\mathsf{4\times4\times4}\\\mathsf{4\times4=16}\\\large\mathsf{16\times4=64}\\\mathsf{2^6 = \bf{64}}

\mathsf{4^4=4\times4\times4\times4}\\\mathsf{4\times4\times4\times4}\\\mathsf{4\times4=16}\\\mathsf{16\times16}\\\mathsf{16\times16=256}\\\mathsf{4^4=\bf{256}}

\boxed{\boxed{\mathsf{Answer: 64\neq 256}}}\huge\checkmark

\text{Good luck on your assignment and enjoy your day!}

~\frak{Amphitrite1040:)}

6 0
3 years ago
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