Which of the following describes the correct stepwise assembly (in vitro) of the eukaryotic RNA polymerase II preinitiation comp
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Okay, first the clear up. The Homozygous dominate trait is RR and is Red, the Heterozygous trait is Rr and is Pink, and the Homozygous recessive trait is rr and is white.
Part A: The co-dominance or incomplete dominance mixes the colours together, so the phenotype for the Heterozygous Rr flower is pink.
Part B: This question is easiest to explain with a punnet square... so. Diagram attached.
Part C: To get only Heterozygous genotypes, the gardener must cross only White flowers with red flowers. Because both these flowers are homozygous pairs, it means that any offspring created from that group would have a mix of the two. This is clearly seen in the F1 generation of Mendel's experiments for further proof. If any other pair is chosen ie Red with red: all red offspring, white and white, all white offspring. Pink and pink, a 1:2:! ratio. Red and Pink: 1:1 ratio of red and pink. White and pink: 1:1 ratio of pink and white. Red and white: Only pink offspring.
Hope that helps, message if you need it explained.
Part A: The co-dominance or incomplete dominance mixes the colours together, so the phenotype for the Heterozygous Rr flower is pink.
Part B: This question is easiest to explain with a punnet square... so. Diagram attached.
Part C: To get only Heterozygous genotypes, the gardener must cross only White flowers with red flowers. Because both these flowers are homozygous pairs, it means that any offspring created from that group would have a mix of the two. This is clearly seen in the F1 generation of Mendel's experiments for further proof. If any other pair is chosen ie Red with red: all red offspring, white and white, all white offspring. Pink and pink, a 1:2:! ratio. Red and Pink: 1:1 ratio of red and pink. White and pink: 1:1 ratio of pink and white. Red and white: Only pink offspring.
Hope that helps, message if you need it explained.
