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3 years ago

Please help ASAP!!!!

Mathematics

1 answer:

Sedaia [141]3 years ago

7 0

Answer:

The top one (✿◠‿◠)

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Hi please help me, i’ll give brainliest

Licemer1 [7]

Answer:

lol dont u love these answers.

the answer is: NO SOLUTION

Step-by-step explanation:

i swear these are the most annoying lol.

please give me brainliest

btw try using math_way for a future reference.

have a good day!

8 0

3 years ago

How do you solve it?

MatroZZZ [7]

Answer:

i: x=-2, x=1

ii: x=-1/2

Step-by-step explanation:

Quadratic form:

You solve i by using FOIL (First, Outside, Inside, Last) because it is a multiplication problem.

$(x+2)(x-1)=0$

"first" would be $x*x$ , which would equal $x^{2}$

"outside" would be $x*-1$ , which would equal $-1x, or -x$

"inside" would be $2*x$ , which would equal $2x$

"last" would be $2*-1$ , which would equal $-2$

Now you need to combine the terms so that they are one after the other

$x^{2}-x$ $+2x-2$

Combine like terms, and you should get:

$x^{2} +x-2$

i Solution

You need to get the variable by itself.

Subtract two from both sides

$x+2=0\\x=-2$

Add one to both sides.

$x-1=0\\x=1$

ii Solution

Add all the terms.

$x+2+x-1=0\\2x+1=0\\2x=-1\\x=-\frac{1}{2}$

8 0

3 years ago

What is 10(n−2p+2) because i dont know the answer

Zigmanuir [339]

10n - 20p + 20

could i get a heart and branliest

6 0

3 years ago

Read 2 more answers

What number between 35 and 40 has only one and itself as factors?

Sonbull [250]

Answer:

Step-by-step explanation:

You're looking for a prime number.

6 0

3 years ago

Read 2 more answers

please show on graph (with x and y coordinates) state where the function x^4-36x^2 is non-negative, increasing, concave up

babunello [35]

Answer:

$y'' =12x^2 -72=0$

And solving we got:

$x=\pm \sqrt{\frac{72}{12}} =\pm \sqrt{6}$

We can find the sings of the second derivate on the following intervals:

$(-\infty$ Concave up

$x=-\sqrt{6}, y =-180$ inflection point

$(-\sqrt{6}$ Concave down

$x=\sqrt{6}, y=-180$ inflection point

$(\sqrt{6}$ Concave up

Step-by-step explanation:

For this case we have the following function:

$y= x^4 -36x^2$

We can find the first derivate and we got:

$y' = 4x^3 -72x$

In order to find the concavity we can find the second derivate and we got:

$y'' = 12x^2 -72$

We can set up this derivate equal to 0 and we got:

$y'' =12x^2 -72=0$

And solving we got:

$x=\pm \sqrt{\frac{72}{12}} =\pm \sqrt{6}$

We can find the sings of the second derivate on the following intervals:

$(-\infty$ Concave up

$x=-\sqrt{6}, y =-180$ inflection point

$(-\sqrt{6}$ Concave down

$x=\sqrt{6}, y=-180$ inflection point

$(\sqrt{6}$ Concave up

8 0

3 years ago