Answer:
8.20in³
Step-by-step explanation:
Given V = πr²h
r is the radius = 1.5in
h is the height = 6in
thickness of wall of the cylinder dr = 0.04in
top and bottom thickness dh 0.07in+0.07in = 0.14in
To compute the volume, we will find the value of dV
dV = dV/dr • dr + dV/dh • dh
dV/dr = 2πrh
dV/dh = πr²
dV = 2πrh dr + πr² dh
Substituting the values into the formula
dV = 2π(1.5)(6)•(0.04) + π(1.5)²(6) • 0.14
dV = 2π (0.36)+π(1.89)
dV = 0.72π+1.89π
dV = 2.61π
dV = 2.61(3.14)
dV = 8.1954in³
Hence volume, in cubic inches, of metal in the walls and top and bottom of the can is 8.20in³ (to two dp)
Answer:
T + V = 50
2T + (3/2) * V = 90
2T + 1.5V = 90
T = 50 * 1.5 - 90 * 1 / 1 * 1.5 - 2*1 = 30
V = 1 * 90 - 2 * 50 / 1 * 1.5 - 2 * 1 = 20
Step-by-step explanation:
T = 30
V = 20
Answer:
237 ⁹/23% change
Step-by-step explanation:
115=100%
337-155=273 which represents the increase
115=100
273=?
273×100÷115= 237 ⁹/23%
Answer =237⁹/23%
(4y³ + 4y²+8)(6y - 4)
Simplify.
24y⁴ - 16y³ + 24y³ - 16y² + 48y - 32
Add like terms.
24y⁴ + (-16y³ + 24y³) -16y² + 48 - 32
Simplify.
24y⁴ + 8y³ - 16y³ + 16
~Hope I helped!~
I believe that -16 is the answer to the question above.
Hope this helps and please enjoy Brainly! -ZeusROX
