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lisov135 [29]
3 years ago
9

Million dollar question. No joke

Mathematics
1 answer:
kotykmax [81]3 years ago
4 0

Answer:

The answer to your question is the third option

Step-by-step explanation:

If two lines are parallel, they have the same slope.

                        y = 1/2 x + 8

The slope of both lines is 1/2

- Find the line equation

Formula

            (y - y1) = m(x - x1)

Substitution

            (y - 2) = 1/2 (x +2)

Simplifying

             y - 2 = 1/2x + 2/2

             y - 2 = 1/2 x + 1

             y = 1/2 x + 1 + 2

Result

             y = 1/2 x + 3

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URGENT!
Alina [70]
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3 years ago
<img src="https://tex.z-dn.net/?f=f%28x%29%3D%5Cfrac%7B3x-6%7D%7B5-2x%7D" id="TexFormula1" title="f(x)=\frac{3x-6}{5-2x}" alt="f
Svetradugi [14.3K]

i) The given function is

f(x)=\frac{3x-6}{5-2x}

The domain is all real values except the ones that will make the denominator zero.

5-2x=0

-2x=-5

x=2.5

The domain is all real values except, x=2.5.

ii) To find the vertical asymptote, we equate the denominator to zero and solve for x.

5-2x=0

-2x=-5

x=2.5

iii) If we equate the numerator to zero, we get;

3x-6=0

3x=6

This implies that;

x=2

iv) To find the y-intercept, we put x=0 into the given function to get;

f(0)=\frac{3(0)-6}{5-2(0)}.

f(0)=\frac{-6}{5}.

f(0)=-\frac{6}{5}.

v)

The degrees of both numerator and the denominator are the same.

The ratio of the coefficient of the degree of the numerator to that of the denominator will give us the asymptote.

The horizontal asymptote  is y=-\frac{3}{2}.

vi) The function has no common factors that are at least linear.

The function has no holes in it.

vii) This rational function has no oblique asymptotes because it is a proper rational function.

3 0
3 years ago
7m+5(m-1)= -5+12m solve the problem
Ede4ka [16]
First you have to simplify the equation. 7m+5m-5 = -5+12m
Then you can add like terms.
12m-5 = -5+12m
Add 5 to both sides
12m = 0+12m
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4 0
3 years ago
) dy 2x<br> ------ = ---------------<br> dx yx2 + y
larisa86 [58]

Step-by-step explanation:

\dfrac{dy}{dx} = \dfrac{2x}{y(x^2 + 1)}

Rearranging the terms, we get

ydy = \dfrac{2xdx}{x^2 + 1}

We then integrate the expression above to get

\displaystyle \int ydy = \int \dfrac{2xdx}{x^2 + 1}

\displaystyle \frac{1}{2}y^2 = \ln |x^2 +1| + k

or

y = \sqrt{2\ln |x^2 + 1|} + k

where I is the constant of integration.

6 0
2 years ago
Which point is located on the line represented by the equation y+4=-5(x-3)
Genrish500 [490]
The equation of a line that passes through (x1,y1) and has a slope of m is 
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