Question

How do you solve it?

Answer 1

Answer:

i: x=-2, x=1

ii: x=-1/2

Step-by-step explanation:

Quadratic form:

You solve i by using FOIL (First, Outside, Inside, Last) because it is a multiplication problem.

$(x+2)(x-1)=0$

"first" would be $x*x$, which would equal $x^{2}$

"outside" would be $x*-1$, which would equal $-1x, or -x$

"inside" would be $2*x$, which would equal $2x$

"last" would be $2*-1$, which would equal $-2$

Now you need to combine the terms so that they are one after the other

$x^{2}-x$ $+2x-2$

Combine like terms, and you should get:

$x^{2} +x-2$

i Solution

You need to get the variable by itself.

Subtract two from both sides

$x+2=0\\x=-2$

Add one to both sides.

$x-1=0\\x=1$

ii Solution

Add all the terms.

$x+2+x-1=0\\2x+1=0\\2x=-1\\x=-\frac{1}{2}$