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3 years ago

Whats 81:45 in its simplest form?

Mathematics

2 answers:

OLEGan [10]3 years ago

8 0

It is 9/5 which is

1and4¬5 if u need to turn it into a proper fraction

yuradex [85]3 years ago

4 0

<span>81/45 in simplest form is = 9/5</span>

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Is 3/47 a rational number? If it is why?

Alexandra [31]

It is not a rational number it is irrational because the decimal doesn't terminate.

4 0

3 years ago

Read 2 more answers

Find the value of x by using law of sines.

Pavel [41]

Answer:

x = 7.7

Option B

Step-by-step explanation:

$\frac{a}{Sin~A} &=& \frac{b}{Sin~b} \\ \frac{8}{Sin~73^\circ} &=& \frac{x}{Sin~67^\circ} \\ \frac{8}{0.96} &=& \frac{x}{0.92} \\ 0.96x &=& 8 \times 0.92 \\ 96x &=& 8 \times 92 \\ 96x &=& 736 \\ x &=& \frac{736}{96} \\ x&=& \frac{23}{3} \\ &\boxed{x=7.7}&$

∴ value of x is 7.7

3 0

3 years ago

Simplifying Algebraic Expressions ; 7+9(-6+8)

Grace [21]

Start by multiplying the 9 out:

9(-6 + 8y) = -54 + 72y

Then, add the 7:

-54 + 72y + 7

Then simplify the whole thing:

-47 + 72y

7 0

3 years ago

Find the roots of h(t) = (139kt)^2 − 69t + 80

Sonbull [250]

Answer:

The positive value of $k$ will result in exactly one real root is approximately 0.028.

Step-by-step explanation:

Let $h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ , roots are those values of $t$ so that $h(t) = 0$ . That is:

$19321\cdot k^{2}\cdot t^{2}-69\cdot t + 80=0$ (1)

Roots are determined analytically by the Quadratic Formula:

$t = \frac{69\pm \sqrt{4761-6182720\cdot k^{2} }}{38642}$

$t = \frac{69}{38642} \pm \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$

The smaller root is $t = \frac{69}{38642} - \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ , and the larger root is $t = \frac{69}{38642} + \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ .

$h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ has one real root when $\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} = 0$ . Then, we solve the discriminant for $k$ :