I NEED TO KNOW if IM correct<br><br> thanks!

Marc saved 30% of his monthly salary each month. His monthly salary in December was $ 3650. In January, his salary increased by

DiKsa [7]

Marc saved $2,533 in January than in December.

Step by Step calculation.

Given the details below :

Salary In December =$3,650

In January, Increased by 12%

Marc saves 30% of $3,650 in December

New salary can then be calculated as :

= Initial salary * % increase / 100 + Initial salary

= 3,650 * 12 / 100 + 3,650

= 3,650 * 0.12 + 3,650

= 4,088

The difference will now be

= 4,088 - 3650

= $438

Since Marc saves in December 30% of $3,650

= 30% of $3,650

= $1,095

Saves in January

= 1,095 + 438

= $2,533

Learn more here : https://brainly.in/question/36065141

8 0

3 years ago

Read 2 more answers

9X (5 + 3) =<br> + (9 X 3)

Korolek [52]

Answer:

x= 3/8

Step-by-step explanation:

In pic

(hope this helps can I pls have brainlist (crown) ☺️)

4 0

3 years ago

Equation please help me solve 1:4 = 3:x

Aliun [14]

The answer is X = 12 because 3 is 1x3 so 4x3 = 12

7 0

4 years ago

A genetic experiment with peas resulted in one sample of offspring that consisted of 438 green peas and 173 yellow peas.

Andre45 [30]

Answer:

a

The 95% confidence interval is $0.2474 < p < 0.3188$

b

The result obtained does not contradict expectation

Step-by-step explanation:

From the question we are told that

The number of green peas is k = 438

The number of yellow peas is u = 173

Generally the sample size is mathematically represented as

$n = k + u$

=> $n = 438 + 173$

=> $n = 611$

Generally the sample proportion for yellow peas is

$\^ p = \frac{u}{n}$

=> $\^ p = \frac{173}{611 }$

=> $\^ p = 0.2831$

From the question we are told the confidence level is 95% , hence the level of significance is

$\alpha = (100 - 95 ) \%$

=> $\alpha = 0.05$

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }$

=> $E = 1.96 * \sqrt{\frac{ 0.2831 (1- 0.2831)}{611} }$

=> $E = 0.0357$

Generally 95% confidence interval is mathematically represented as

$\^ p -E < p < \^ p +E$

=> $0.2831 -0.0357$

=> $0.2474 < p < 0.3188$

From the question we are told that it was expected that 25% of the offspring peas will be yellow

Now from the 95% confidence interval obtained we see that the expected sample proportion(25% ) falls within it so it means that the result obtained does not contradict expectation

7 0

3 years ago

3 2/5x1/2 help find the answer asap

babunello [35]

Answer

1 7/10

Step-by-step explanation:

(3 2/5)(1/2)=17/5=1 7/10

5 0

3 years ago

I NEED TO KNOW if IM correct thanks!