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madreJ [45]
3 years ago
12

What is the solution (x,y) to the system of equations below x + 9y = 3 y= 1/3 x + 7

Mathematics
1 answer:
Alex_Xolod [135]3 years ago
4 0

Let's solve this by substitution.


y is given by the 2nd eqn as y = (1/3)x + 7. Subst. (1/3)x + 7 into the first eqn as a replacement for y: x + 9( (1/3)x + 7) = 3.


clear out fractions by mult. all 3 terms by 3: 3x + 9x + 63 = 3


Combine like terms: 12x = -60. Then x = -5


Find y by subst. -5 for x in the 2nd equation: y = (1/3)(-5) + 7

= -5/3 + 35/3 = 30/3 = 10.


Thus, the solution (x,y) of this system is (-5,10).


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Parallel is the answer
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3 years ago
PLEASE HELP. WILL GIVE BRAINLIEST
KengaRu [80]

Answer:

x-intercepts = 1,2, and 4, y-intercept = -8

Step-by-step explanation:

x^3 - 7x^2 - 14x - 8 in factored form is equal to (x-1)(x-2)(x-4).

Solving for x-intercepts:

  • We are actually able to solve for all x-intercepts without the given factor. But since we are given one of the factors, our job becomes much easier.
  • Using synthetic division, or long division, we factor out the x-intercept 4. Which leaves us with the polynomial x^2 - 3x + 2.
  • From here we can separate the polynomial into two binomials.
  • x^2 - 3x + 2 = (x-1)(x-2). Giving us all 3 x-intercepts.
  • Using Descartes' rules we can identify before even starting the problem how many real x-intercepts there are (Not needed for this problem).

Solving for y-intercept:

  • The y-intercept is always the coefficient that does not have any assigned x-variables.
  • The coefficient is -8, thus the y-intercept.
  • If unsure of the y-intercept, you can always plug in x = 0. Solving for the y-intercept will give you the value of f(0).
  • If there is no coefficient, the y-intercept is equal to zero.
4 0
3 years ago
Solve the following system of equations algebraic<br> y=x^2+3x-29<br> y=2x-9
Lady bird [3.3K]

Step-by-step explanation:

Given equations:

       y  = x² + 3x - 29    ------ (i)

       y  = 2x - 9  ---------------- (ii)

Now to solve this problem, we must determine the value of x and y;

 Equate equations 1 and 2;

       x² + 3x - 29 = 2x - 9

       x² + 3x - 2x - 29 + 9  = 0

       x² + x - 20  = 0

       x² + 5x - 4x - 20  = 0

       x(x + 5 ) - 4(x + 5) = 0

      (x - 4) (x+ 5) = 0

       x  - 4  = 0 or x + 5  = 0

      x  = 4 or x = -5;

So;   solve for y now;

     y = 2x - 9

     input x  = 4 or x = -5;

    y  = 2(4) - 9 or y = 2(-5) - 9

    y = -1 or y = -19

7 0
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It is your first semester at college and you take out a $5000 loan and in order to pay off that loan by the end of the semester
kakasveta [241]

Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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7 0
3 years ago
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