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Mathematics

1 answer:

WARRIOR [948]3 years ago

8 0

The answer is 81 because if we plug in 9:

9^2 * 9^0

We know that anything to the zero power is one, so we are left with

9^2 which equals 81

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Which of the functions below could have created this graph?

Brums [2.3K]

Answer:

need pic

Step-by-step explanation:

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3 years ago

What are potential roots of p(x) = x4 + 22x2 – 16x – 12

kow [346]

Simplify 22\times 222×2 to 4444
{x}^{4}+44-16x-12x4+44−16x−12Collect like terms
{x}^{4}+(44-12)-16xx4+(44−12)−16x Simplify{x}^{4}+32-16xx4+32−16x

8 0

3 years ago

Read 2 more answers

What is the area of the shaded region?

kolezko [41]

Answer:

110 cm^2

Step-by-step explanation:

The first thing that you need to do is find the area of triangle AFE. The area of a triangle is always base*height/2. So in this case, that would be 10*6 divided by 2, which is 30 cm. Next, you will need to know the area of triangle ECB. Using that same formula, you will get 8*10/2, which is 40 cm. Finally, you will need to find the area of the whole rectangle. The area of a rectangle is always the length times the width. In this case, you would have 10*18, which is 180 cm. To get your final answer, you need to subtract the areas of the unshaded area from the whole area. That would be 180-(30+40), which is 110 cm. I hope this helped!

6 0

2 years ago

Suppose you pay $1.00 to roll a fair die with the understanding you will get $3.00 back rolling a 4 or a 2, and nothing otherwis

nikdorinn [45]

There are 2 chances out of 6 to win $3

Every 6 rolls you are expected to win $6

Every 3 rolls you are expected to win $3.

On average, even though it's impossible, every roll you would make $1.

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3 years ago

Which of the following are solutions to the equation below?

Natasha2012 [34]

Both A and C would be solutions to the equation.

In order to solve for this you must first get the equation equal to 0.

2x^2+5x+8=6 ----> subtract 6 from both sides
2x^2 + 5x + 2 = 0

Now knowing this we can use the coefficients of each one in descending order of power as a, b and c.

a = 2 (because it is the coefficient to x^2)
b = 5 (because it is the coefficient to x)
c = 2 (because it is the end number)

Now we can plug these values into the quadratic equation.

$\frac{-b +/- \sqrt{b^{2} - 4ac } }{2a}$

$\frac{-5 +/- \sqrt{5^{2} - 4(2)(2) } }{2(2)}$

$\frac{-5 +/- \sqrt{9} }{4}$

$\frac{-5 +/- 3 }{4}$

$\frac{-5 + 3 }{4}$ or -1/2 for the first answer

$\frac{-5 - 3 }{4}$ or -2 for the second answer

5 0

3 years ago