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3 years ago

Solve each system of eaquasions x+4y=4 -x+2y=8

Mathematics

2 answers:

bazaltina [42]3 years ago

6 0

X + 4y = 4
-x + 2y = 8

x + 4y - x + 2y = 4 + 8

6y = 12

y = 2

x + 4(2) = 4
x + 8 = 4
x = -4

(x,y)
(-4,2)

Annette [7]3 years ago

6 0

Answer:

(-4, 2)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Distributive Property

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Terms/Coefficients
Coordinates (x, y)
Solving systems of equations using systems

Step-by-step explanation:

Step 1: Define Systems

x + 4y = 4

-x + 2y = 8

Step 2: Rewrite Systems

x + 4y = 4

[Subtraction Property of Equality] Subtract 4y on both sides: x = 4 - 4y

Step 3: Redefine Systems

x = 4 - 4y

-x + 2y = 8

Step 4: Solve for y

Substitution

Substitute in x: -(4 - 4y) + 2y = 8
[Distributive Property] Distribute negative: -4 + 4y + 2y = 8
Combine like terms: -4 + 6y = 8
[Addition Property of Equality] Add 4 on both sides: 6y = 12
[Division Property of Equality] Divide 6 on both sides: y = 2

Step 5: Solve for x

Define original equation: x + 4y = 4
Substitute in y: x + 4(2) = 4
Multiply: x + 8 = 4
[Subtraction Property of Equality] Subtract 8 on both sides: x = -4

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Solve each system of eaquasions x+4y=4 -x+2y=8​

Solve each system of eaquasions x+4y=4 -x+2y=8