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Wewaii [24]
4 years ago
6

What are the two solutions of the equation? x = StartRoot 5 EndRoot and x = negative StartRoot 5 EndRoot x = 3 + StartRoot 5 End

Root and x = 3 – StartRoot 5 EndRoot x = 5 + StartRoot 3 EndRoot and x = 5 – StartRoot 3 EndRoot x = StartRoot five-thirds EndRoot and x = negative StartRoot five-thirds EndRoot
Mathematics
2 answers:
valentinak56 [21]4 years ago
8 0

Answer:

x = 3 + StartRoot 5 EndRoot and x = 3 – StartRoot 5 EndRoot

Step-by-step explanation:

Luda [366]4 years ago
4 0

Answer:

its b on ed

Step-by-step explanation:

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Help me pls! ill rate you very good!!!!
JulsSmile [24]

Answer:

The answer is L

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Johan found that the equation –2|8 – x| – 6 = –12 had two possible solutions: x = 5 and x = –11. Which explains whether his solu
lutik1710 [3]

Answer:

we have two solution x = 5 and x = 11

but in given problem x = 5 and x = –11

thus, only one of his solution x = 5 is correct

Step-by-step explanation:

Given

–2|8 – x| – 6 = –12

adding 6 both sides

–2|8 – x| – 6 +6= –12 +6

–2|8 – x|  = –6

dividing both side by -2

–2|8 – x| /-2 = –6/-2

=>|8 – x|  = 3

we know that

in modulus function |Y| = -y or y

Thus

|8 – x|  = 3

can be written as

8-x = 3   or          8- x = -3

8-x-3 = 0  or      8-x+3 = 0

5-x = 0     or      11 -x = 0

x = 5       or x = 11

thus, we have two solution x = 5 and x = 11

but in given problem x = 5 and x = –11

thus, only one of his solution x = 5 is correct

8 0
3 years ago
-8x2(x+8)=8(2+6) how do i solve this and 4n+3/2=2n-5/1?
Marat540 [252]

1) -8x^2\left(x+8\right)=8\left(2+6\right)

-8x^3-64x^2=64

-8x^3-64x^2-64=64-64

-8x^3-64x^2-64=0

-8x^2+0.97035\dots x-7.88051\dots \approx \:0

x\approx \:-8.12129\dots

2) 4n+\frac{3}{2}=2n-\frac{5}{1}

4n+\frac{3}{2}=2n-5

4n+\frac{3}{2}-\frac{3}{2}=2n-5-\frac{3}{2}

4n=2n-\frac{13}{2}

4n-2n=2n-\frac{13}{2}-2n

2n=-\frac{13}{2}

\frac{2n}{2}=\frac{-\frac{13}{2}}{2}

n=-\frac{13}{4}

6 0
3 years ago
if △ ABC ~ △A'B'C' and AC=20cm,A'C'=15cm,B'C'=12cm andA'B'=9cm find the lengths of the other sides of △ABC.​
zlopas [31]

Answer:

AB=12    BC=9

Step-by-step explanation:

Any side of a triangle must be shorter than the other two sides added together.

AB and A'B' must measure LESS than  the other 2 sides

  15 is 3/4 of 20

   12 is 3/4 0f 9

 

20/15   12/9    = 1.3333333........

6 0
2 years ago
What's the equivalent fraction. Of 9/30
GalinKa [24]

9/30, Divide by 3

9/30= 3/10

3/10 is Equivalent to 9/30

5 0
4 years ago
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