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IRINA_888 [86]
3 years ago
7

The three vertices of a triangle drawn on a complex plane are represented by 0 + 0i, 4 + 0i, and 0+ 3i.

Mathematics
1 answer:
QveST [7]3 years ago
4 0
Thank you for posting your question here at brainly. Below is the solution for the above problem. I hope the answer will help you. 

<span>a² + b² = c²
3² + 4² = c²
25 = c²
c = 5</span>
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which number is a prime factor of 210 A.2 to the 6th power B.6 to the 2nd power or 6 squared C.12 to the 6th power.Exponents and
Elden [556K]
210=2*3*5*7
none of them

if you meant 2¹⁰ then the answer is A because 2¹⁰=2*2*2*2*2*2*2*2*2*2=(2⁶)(2⁴)


A
8 0
3 years ago
Match the solid figure to the appropriate formula.
Zinaida [17]
<span>1. A = 1/4s squared, square root of 3      equilateral triangle
2. A = bh                                                  rectangle  
3. A = pi(r) squared                                  circle area 
4. A = 1/2 h (b1+ b2)                                trapezoid
5. C = pi(d)                                               circle circumference 
6. A = base x altitude                               parallelogram
7. A = 1/2(ap)                                           regular polygon
8. A = 1/2(bh)                                           triangle

</span><span>- regular polygon
- trapezoid
- parallelogram
- circle circumference
- equilateral triangle
- circle area</span>
4 0
3 years ago
PLEASE HELP FAST!!!!!!!!
seropon [69]

Answer:

Option B. -j = -h/-k is not correct

Step-by-step explanation:

As from the given scenario both the negative signs will be cancelled out giving positive j : -h/-k = -j

First option has: -j = -h/k In this case also the negative sign from both sides would be cancelled out.

Second option has: -h/-k = -j In this case negative signs cannot be cancelled out.

Third option has: h/-k = -j , negative sign would be cancelled from both sides.

Fourth option has: h/k = j , no negative sign on either side.

i hope it will help you!

7 0
3 years ago
Write an equation of a line that passes through (-12, -14) with slope 6.
damaskus [11]

The slope intercept form of a line is y = mx + b

  • m = slope
  • b = y-intercept

Plug in the slope, 6, into m.

Rewrite the equation;

  • y = 6x + b
  • We need to find b, your y-intercept, to finish this equation.

Plug in your point coordinate, (x, y) ⇒ (-12, -14) into the equation.

  • -14 = 6(-12) + b

Solve for b to find the y-intercept.

  • -14 = -72 + b
  • 58 = b

Your new equation (your answer) is<em> </em>y = 6x + 58.

6 0
3 years ago
Please help fassssst
Zarrin [17]

Answer:

\dfrac{9}{2}

Step-by-step explanation:

You can do this using the quadratic equation:

x =\dfrac{-b\pm\sqrt{b^{2}-4ac}}{2a}

Let's first setup our expression:

4x² + 12x = 135

the quadratic formula is:

ax² + bx + c = 0

4x² + 12x - 135 = 0

Then:

a = 4

b = 12

c = -135

Now we plug in our coefficients and solve:

x =\dfrac{-12\pm\sqrt{12^{2}-4(4)(-135)}}{2(4)}

We solve for both to determine the positive one:

x =\dfrac{-12+ \sqrt{12^{2}-4(4)(-135)}}{2(4)}              x =\dfrac{-12- \sqrt{12^{2}-4(4)(-135)}}{2(4)}

x =\dfrac{-12+ \sqrt{144+2160}}{8}                        x =\dfrac{-12- \sqrt{144+2160}}{8}

x =\dfrac{-12+ \sqrt{2304}}{8}                                 x =\dfrac{-12- \sqrt{2304}}{8}

x =\dfrac{-12+ 48}{8}                                        x =\dfrac{-12- 48}{8}

x =\dfrac{36}{8} = \dfrac{9}{2}                                           x =\dfrac{-60}{8} = \dfrac{-15}{2}

So if you are looking for a positive solution, just take the positive one as x.

8 0
3 years ago
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