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yaroslaw [1]
3 years ago
6

Can someone please help me?

Mathematics
2 answers:
Keith_Richards [23]3 years ago
8 0
Because the angles of both triangles are equal, they are similar triangles, and because they share side JL, they are congruent triangles. due to this, the length of side KJ=JM, therefore 2x-7=3x-16. solving this for x, we get that x=9. And because KJ=2x-7, plugging in 9 for x we get that KJ=11 m
Rama09 [41]3 years ago
4 0
Yes I can help. what do you need
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X 3) Find the product of 3 x 4 2/3 * O 18 3/4 O 12 6/3 or 14 o 71/2 (0) 14​
ladessa [460]

D. \: 14 \: ✅

Step-by-step explanation:

3 \times 4 \frac{2}{3}  \\  = 3 \times  \frac{14}{3}  \\ =   14

\circ \: \: { \underline{ \boxed{ \sf{ \color{green}{Happy\:learning.}}}}}∘

5 0
3 years ago
Read 2 more answers
4w^2+49=-28w solve for w<br><br> plz answer
boyakko [2]

Move all terms to one side

4w^2 + 49 + 28w = 0

Rewrite 4w^2 + 49 + 28w in the form a^2 + 2ab + b^2, where a = 2w and b = 7

(2w)^2 + 2(2w)(7) + 7^2 = 0

Use the Square of Sum: (a + b)^2 = a^2 + 2ab + b^2

(2w + 7)^2 = 0

Take the square root of both sides

3w + 7 = 0

Subtract 7 from both sides

2w = -7

Divide both sides by 2

<u>w = -7/2</u>

3 0
3 years ago
Solve triangle ABC given that C=32 degrees, b=8 and a=3 round the answer to the nearest hundredth
irga5000 [103]
The triangle would be an acute triangle at 43 degrees
4 0
3 years ago
Calculate the following:
I am Lyosha [343]
<span>-11 /7 * 7 /5</span>= -2(1/5)

4 0
3 years ago
Read 2 more answers
You calculated probabilities involving various blood types. Some of your answers depended on the assumption that the outcomes de
Natali5045456 [20]

Answer:

a) The events are disjoint, because a person cannot have blood type A and blood type B at the same time.

b) The events are independent, because the probability of having blood type does not depend on other persod having blood type B.

c) Yes, disjoint events are independent if and only if the probability of some of the events is zero.

Step-by-step explanation:

a) Let the events be:

A: "the person has blood type A

B: the person has blood type B

As a person can only have one blood type these events are disjoint.

b) If we examine two people, let the events be that the first is blood Type A and the second blood Type B:

The events are independent because the probability of the first person having blood type A does not influence the probability of the second person having blood type B (unless the two people are related).

c) Two events are independent if and only if:

P(A∩B)=P(A)×P(B)

Given the events A and B which are disjoint:

P(A∩B)=0

Hence, A and B could be independent events if and only if the probability of one of the events is 0.

3 0
3 years ago
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