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Liono4ka [1.6K]
3 years ago
6

Please Help!

Mathematics
1 answer:
Anna71 [15]3 years ago
6 0

9514 1404 393

Answer:

  51 square inches

Step-by-step explanation:

This can be considered a couple of ways:

  1. a 6 in × 7 in rectangle with a 6 in × 3 in triangle added on
  2. a 6 in × 13 in rectangle with a 6-in high trapezoid cut from the lower right corner.

The formulas for areas of these figures are ...

  A = 1/2bh . . . . area of triangle with base b and height h

  A = 1/2(b1 +b2)h . . . . area of a trapezoid with bases b1, b2, and height h

  A = bh . . . . . . . area of a rectangle with base b and height h

__

1. rectangle area = (6 in)(7 in) = 42 in²

  triangle area = 1/2(6 in)(3 in) = 9 in²

Total area of the figure:

  42 in² +9 in² = 51 in²

__

2. rectangle area = (6 in)(13 in) = 78 in²

  trapezoid area = 1/2(6 in + 3 in)(6 in) = 27 in²

Total area of the figure:

  78 in² -27 in² = 51 in²

The area of the composite shape is 51 square inches.

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Answer:

Yes, he will have enough 3 over 8 ft pieces for his class.

Step-by-step explanation:

Given:

Number of wood required = 22

Length of each wood, l=\frac{3}{8}\textrm{ ft}

Total length of the board, L=9\textrm{ ft}

Therefore, the number of woods that can be made using the given board is given as:

\textrm{Number of woods made}=\frac{\textrm{Total length of board}}{\textrm{Length of each wood}}\\\textrm{Number of woods made}=\frac{L}{l}=\frac{9}{\frac{3}{8}}=9\times \frac{8}{3}=\frac{72}{3}=24

So, he can make 24 woods of length \frac{3}{8}\textrm{ ft} using the 9 ft board. But he has to make only 22 pieces.

Therefore, he has enough of the wood to make the required number of pieces.

3 0
3 years ago
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