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3 years ago

Given y²+5y-6= (y+p) (y+q), find the values of p and q.

Mathematics

2 answers:

Flauer [41]3 years ago

8 0

Answer:

p = 6, q = - 1 , or p = - 1, q = 6

Step-by-step explanation:

Factorise the quadratic expression on the left side

y² + 5y - 6

Consider the factors of the constant term (- 6) which sum to give the coefficient of the y- term (+ 5)

The factors are + 6 and - 1 , since

6 × - 1 = - 6 and 6 - 1 = + 5 , then

y² + 5y - 6

= (y + 6)(y - 1) = (y - 1)(y + 6)

Compare to (y + p)(y + q) , then

p = 6, q = - 1 or p = - 1, q = 6

alina1380 [7]3 years ago

7 0

Answer:

(y+6)(y-1)

Step-by-step explanation:

literally factorising.

y^2 x -6 = -6y^2

u need two numbers that multiply to make -6 and add them together to make +5 which is +6 and -1.

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PLEASE HELP! BRAINLIEST!!!!!!! PLEASE

Gnesinka [82]

Hello!

First you have to find the volume of the cylinder

To find the volume of a cylinder you use the equation

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Put in the values you know and 3.14 for pi

$V = 3.14 * 3^{2} * 7$

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V = 3.14 * 9 * 7

Multiply

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Next you find the volume of the sphere

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Put in the values you know and 3.14 for pi

$V = \frac{4}{3} * 3.14 * 3^{3}$

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Finally you subtract the two volumes from each other

197.82 - 113.04 = 84.78
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The answer is C)84.78

Hope this helps!

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Given y²+5y-6= (y+p) (y+q), find the values of p and q. ​

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