Given y²+5y-6= (y+p) (y+q), find the values of p and q.
2 answers:
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The given pair of lines are not perpendicular.
<h3>What is a line?</h3>The line is a curve showing the shortest distance between 2 points.
5x - 5y = -2 - - - - - (1)
Transform the equation into standard form,
5x + 2 = 5y
y = 5x /5 + 2/5
y = x + 2/5
The slope of equation 1 is and intercept c = 2 / 5
Similarly
x + 2y = 4 - - - - - - - -(2)
Transform it into standard form
y = -x/2 + 4 /2
y = -x / 2 + 2
Slope of the equation 2 = -1 / 2 and intercept c = 2
Slope of line 1 * slope of line 2 = 1 * -1/2 = -1/2
Since the lines are not perpendicular because the pair of lines does not satisfy the property of perpendicular lines i.e
Thus, the given pair of lines are not perpendicular.
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