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3 years ago

Help!!!!! Not the top one by the way..!

Mathematics

1 answer:

OverLord2011 [107]3 years ago

3 0

Answer:

$\large\boxed{x=-3\ and\ y=-11\to(-3,\ -11)}$

Step-by-step explanation:

$\underline{+\left\{\begin{array}{ccc}-6x+y=7\\3x-y=2\end{array}\right}\qquad\text{add both sides of the equations}\\\\.\qquad-3x=9\qquad\text{divide both sides by (-3)}\\.\qquad\boxed{x=-3}\\\\\text{Put the value of x to the first equation:}\\\\-6(-3)+y=7\\18+y=7\qquad\text{subtract 18 from both sides}\\\boxed{y=-11}$

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Researchers fed mice a specific amount of Dieldrin, a poisonous pesticide, and studied their nervous systems to find out why Die

Elodia [21]

Answer:

Step-by-step explanation:

Part A

Mean = (2.2 + 2.4 + 2.5 + 2.5 + 2.6 + 2.7)/6 = 2.48

Standard deviation = √(summation(x - mean)²/n

n = 6

Summation(x - mean)² = (2.2 - 2.48)^2 + (2.4 - 2.48)^2 + (2.5 - 2.48)^2 + (2.5 - 2.48)^2 + (2.6 - 2.48)^2 + (2.7 - 2.48)^2 = 0.1484

Standard deviation = √(0.1484/6

s = 0.16

Standard error = s/√n = 0.16/√6 = 0.065

Part B

Confidence interval is written as sample mean ± margin of error

Margin of error = z × s/√n

Since sample size is small and population standard deviation is unknown, z for 98% confidence level would be the t score from the student t distribution table. Degree of freedom = n - 1 = 6 - 1 = 5

Therefore, z = 3.365

Margin of error = 3.365 × 0.16/√6 = 0.22

Confidence interval is 2.48 ± 0.22

Part C

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

H0: µ = 2.3

For the alternative hypothesis,

H1: µ > 2.3

This is a right tailed test

Since the number of samples is small and no population standard deviation is given, the distribution is a student's t.

Since n = 6

Degrees of freedom, df = n - 1 = 6 - 1 = 5

t = (x - µ)/(s/√n)

Where

x = sample mean = 2.48

µ = population mean = 2.3

s = samples standard deviation = 0.16

t = (2.48 - 2.3)/(0.16/√6) = 2.76

We would determine the p value using the t test calculator. It becomes

p = 0.02

Assuming significance level, alpha = 0.05.

Since alpha, 0.05 > than the p value, 0.02, then we would reject the null hypothesis. Therefore, At a 5% level of significance, the sample data showed significant evidence that the mean absolute refractory period for all mice when subjected to the same treatment increased.

6 0

3 years ago

Which set of ordered pairs could represent a function? (2, 3), (2, 2), (2, 4), (2, 9), (2, –2) (1, 5), (2, 6), (1, 6), (4, 5), (

Ratling [72]

Given:

The set of ordered pairs in the options:

(a) (2, 3), (2, 2), (2, 4), (2, 9), (2, –2)

(b) (1, 5), (2, 6), (1, 6), (4, 5), (1, 4)

(d) (5, 1), (7, 3), (9, 5), (11, 7), (13, 9)

To find:

The set of ordered pairs that could represent a function.

Solution:

A set of ordered pairs represent a function, if there exist unique output (y-value) for each input (x-value).

In option (a) we have, five output values y=3,2,4,9,-2 for single input x=2. So, it is not a function.

In option (b) we have, three output values y=5,6,4 for single input x=1. So, it is not a function.

In option (c) we have, two output values y=0,3 for single input x=1. So, it is not a function.

In option (d), all inputs has unique output.

Therefore, the correct option is (d).

4 0

3 years ago

Read 2 more answers

(1/3)^x^1/4 • (1/3)^x^2/3

monitta

Wait i’m confused on how this equation is modeled i’m sorry do you have a picture? i wanna be sure i answer this right.

5 0

3 years ago

A machine is used to fill bags with sand. the average weight of a bag filled with sand is 22.3 pounds. Write an absolute value f

frutty [35]

Answer:

$y=f(x)=|x-22.3|$

Step-by-step explanation:

Let the weight of the bag of sand with an unknown weight be given as "x" pounds. Then, the difference between the weight of an average bag of sand which is given to be as 22.3 pounds, is given as $x-22.3$ . Therefore, the absolute value function describing the difference between the weight of an average bag of sand and a bag of sand with an unknown weight will be given as: $|x-22.3|$ .

Let us represent this by f(x) or y. And thus, we get:

$y=f(x)=|x-22.3|$

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4 years ago

The height of a triangle is 6 units less than twice the base length if the height is 18 units, what is the base length

Dimas [21]

Answer:

12 units

Step-by-step explanation:

h=2x-6

18=2x-6

24=2x

12=x

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3 years ago