Given :
Area of rectangle.
To Find :
The dimensions of a rectangle (in m) with area 1,728 m2 whose perimeter is as small as possible.
Solution :
Let, the dimensions of rectangle is x and y.
Area, A = xy.
x = A/y. ....1)
Perimeter, P = 2( x + y )
Putting value of x in above equation, we get :
For minimum P,
SO, it is a square.
Therefore, the dimensions are 
.24\sqrt{3}
Hence, this is the required solution.
If this a ratio, then the simplified form would be 2cm : 1cm I believe (6/3 = 2 and 3/3 = 1 so 2:1)
The branch of science that deals with the identification of the substances of which matter is composed; the investigation of their properties and the ways in which they interact, combine, and change; and the use of these processes to form new substances
Okay so.
2/5=24/60 (multiply 2/5 by 12)
2/3=40/60 (multiply 2/3 by 20)
1/4=15/60 (multiply 1/4 by 15)
Then,
Add 24/60 with 40/60 which is 64/60 after you get that you subtract by 15/60 and you get 49/60.
Hope this helps!^^
