Can someone please help me
2 answers:
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Answer:
0.2081 = 20.81% probability that at least one particle arrives in a particular one second period.
Step-by-step explanation:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:
In which
x is the number of sucesses
e = 2.71828 is the Euler number
is the mean in the given interval.
Over a long period of time, an average of 14 particles per minute occurs. Assume the arrival of particles at the counter follows a Poisson distribution. Find the probability that at least one particle arrives in a particular one second period.
Each minute has 60 seconds, so
Either no particle arrives, or at least one does. The sum of the probabilities of these events is decimal 1. So
We want . So
In which
0.2081 = 20.81% probability that at least one particle arrives in a particular one second period.
The equation of the graph y= has no symmetry
The equation of the graph y =
Replace y with -y in the given equation
-y =
When replacing y with -y gives the different equation. The equation is not symmetric with respect to x axis
Replace x with -x in the given equation
y =
y =
When replacing x with -x gives the different equation. The equation is not symmetric with respect to y axis
Replace x with -x and y with -y in the equation
-y =
-y =
When replacing x with -x and y with -y gives the different equation. The equation is not symmetry with respect to origin.
Hence, the equation of the graph y= has no symmetry
Learn more about symmetry here
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