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Elan Coil [88]
3 years ago
14

Factor the GCF: 9x4y − 6x3y2 + 3x2y3.

Mathematics
1 answer:
Ganezh [65]3 years ago
7 0
For this case we have the following expression:
 9x^4y - 6x^3y^2 + 3x^2y^3

 For this case what you should do is observe the terms that are repeated in the given expression.
 We have then:
 3x^2y

 It is the term that is present in the whole expression.
 Therefore, by doing common factor we have:
 3x^2y (3x^2 - 2xy + y^2)

 Answer:
 
the GCF is:
 3x^2y (3x^2 - 2xy + y^2)
 option A: a 3 is missing at the beginning of the option.
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Answer:

309

Step-by-step explanation:

a = 3, d = 6, n 52

Nth term of an Arithmetic sequence is given as:

t_n=a +(n-1)d \\  \therefore \: t_{52}=3 +(52-1) \times 6 \\ \therefore \: t_{52}=3 +51\times 6 \\  \therefore \: t_{52}=3 +306 \\   \huge \red{ \boxed{\therefore \: t_{52}=309 }}\\

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Help Solve Domain and Range
Zielflug [23.3K]

You would likely benefit far more from learning the definitions of "domain" and "range" than from being given the domain and range in each of these cases.

The domain of a function includes all values of the independent variable for which the function is defined (that is, for which there is a graph). In Case 1, x can have any real value, and so the domain is (-infinity, infinity).

The range of a function includes all values that the dependent value can have (that is, for which there is a graph). In Case 1, y can take on any real value, and so the range is (-infinity, infinity).


Contrast this case to Case 2. Here, y has only ONE value, so the range is simply y=2, or {2}. x can take on any value, so the domain is (-infinity, infinity).

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<img src="https://tex.z-dn.net/?f=x%20%5E%7B2%7D%20%20-%208x%20%3D%203" id="TexFormula1" title="x ^{2} - 8x = 3" alt="x ^{2} -
Nat2105 [25]

Answer:

x = 4 + \sqrt{19}

Step-by-step explanation:

To solve by factoring, complete the square by dividing 8 from 8x in 2. Then square the result 4 to get 16. Add 16 to both sides.

x^2 -8x = 3\\\\x^2 - 8x + 16 = 3 + 16\\\\(x-4)^2 = 19

The equation is now factored. To solve, take the square root of both sides and solve for x.

\sqrt{(x-4)^2}  = \sqrt{19}\\\\x-4 = \sqrt{19} \\\\x = 4 + \sqrt{19}

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