9514 1404 393
Answer:
38.5°
Step-by-step explanation:
A triangle solver can give an answer easily. The angle is 38.5°.
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The law of cosines can be written to solve for an unknown angle C opposite side 'c' and flanked by sides 'a' and 'b'.
C = arccos((a² +b² -c²)/(2ab))
Here, we have a=35, b=48, c=30, so the angle is ...
C = arccos((35² +48² -30²)/(2·35·48)) = arccos(2629/3360) ≈ 38.515°
The angle the cable makes with the pole is about 38.5°.
10 3/5=10.6
10.6+12.5=23.1
35.0-23.1=11.9
It is 11.9 miles from Chester to Durbin.
Answer:
1. 0 and 1
2. about 0.6
3. 2 and 3
4. about 2.2
Step-by-step explanation:
Took the assignment