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elixir [45]
3 years ago
10

Solve 3x^2=-12-6x by completing the square​

Mathematics
1 answer:
Lelu [443]3 years ago
3 0

Answer:

x = - 1 ± i \sqrt{3}

Step-by-step explanation:

Given

3x² = - 12 - 6x ( add 6x to both sides )

3x² + 6x = - 12 ( divide through by 3 )

x² + 2x = - 4

To complete the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(1)x + 1 = - 4 + 1

(x + 1)² = - 3 ( take the square root of both sides )

x + 1 = ± \sqrt{-3} = ± i \sqrt{3} ( subtract 1 from both sides )

x = - 1 ± i \sqrt{3}

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Answer:

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Y,           X

1,           448

2,          446

3,         444

4,          442

5,          440

6,          438

7,          436

8,          434

9,          432

10,          430

11,          428

12,          426

13,          424

14,          422

15,          420

16,            418

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3 years ago
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