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3 years ago

I really need help on this please.

Mathematics

2 answers:

yuradex [85]3 years ago

6 0

Answer:

37°

Step-by-step explanation:

39 = 1/2(41 + DE)

78 = 41 + DE

37 = DE

mamaluj [8]3 years ago

3 0

Answer: 39

Step-by-step explanation:

Because the vertex of the angle is at the center of the circle, the arc would be equal to it. Hope this helped:)

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Given that point A is the midpoint of line segment ED, where E( -1,9) and A(4,5), what is the location of point D?

yuradex [85]

Answer:

D(9, 1)

Step-by-step explanation:

A being the midpoint means its coordinates satisfy ...

A = (E + D)/2

Solving for D, we find ...

D = 2A -E

= 2(4, 5) -(-1, 9) = (2·4 +1, 2·5 -9)

D = (9, 1)

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3 years ago

0.5 to the second power x (20-2 to the third power x 3)x(2/5x25)

lesantik [10]

Answer:

489

Step-by-step explanation:

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3 years ago

I never see to pretty best friend one of them got to be ugly. if you know you know

Elina [12.6K]

Answer:lol

Step-by-step explanation:

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3 years ago

Read 2 more answers

Find y so (-2, y) is a solution to 3x+5y=8

Yuri [45]

Answer:

y=14/5 or 2.8

Step-by-step explanation:

3(-2)+5y=8

-6+5y=8

+6 +6

5y=14

/5y /5y

y=14/5

4 0

2 years ago

A new screening test for Lyme disease is developed for use in the general population. The sensitivity and specificity of the new

Anit [1.1K]

Answer:

predictive value of a positive test = 18.18%

predictive value of a negative test = 94.03%

Step-by-step explanation:

Sensitivity = 60% = 0.6

Specificity = 70% = 0.7

Let True Positive = TP

True Negative = TN

False Negative = FN

$Sensitivity = \frac{TP}{TP + FN} \\0.6 = \frac{TP}{TP + FN} \\0.6TP + 0.6FN = TP\\0.4TP = 0.6FN\\TP = 1.5 FN$

$Specificity = \frac{TN}{TN + FP} \\0.7 = \frac{TN}{TN + FP} \\0.7TN + 0.7FP = TN\\0.7FP = 0.3 TN\\TN = 7/3 FP$

Prevalence = 10% = 0.1

Three hundred people are screened, $T_{total} = 300$

Total number of people having the disease, $T_{disease} = ?$

$Prevalence = \frac{T_{disease} }{T_{total} } \\0.1 = \frac{T_{disease} }{300 }\\T_{disease} = 30$

$T_{disease} = TP + FN\\30 = TP + FN$

But TP = 1.5 FN

30 = 1.5 FN + FN

30 = 2.5 FN

FN = 30/2.5

FN = 12

TP = 1.5 FN = 1.5 * 12

TP = 18

$FP + TN = T_{total} - T_{disease} \\FP + TN = 300 - 30\\FP + TN = 270\\FP + \frac{7}{3} FP = 270\\\frac{10}{3} FP = 270\\FP = 27 * 3\\FP = 81$

81 + TN = 270

TN = 189

To calculate the Predictive value of positive test (PPT)

$PPT = \frac{TP}{TP + FP} * 100\\PPT = \frac{18}{18+81} * 100\\PPT = \frac{18}{99} * 100\\PPT = 18.18 \%$

To calculate the Predictive value of negative test (PNT)

$PPT = \frac{TN}{FN + TN} * 100\\PPT = \frac{189}{189+12} * 100\\PPT = \frac{189}{201} * 100\\PPT = 94.03 \%$

7 0

3 years ago