<u>Given</u>:
Given that the data are represented by the box plot.
We need to determine the range and interquartile range.
<u>Range:</u>
The range of the data is the difference between the highest and the lowest value in the given set of data.
From the box plot, the highest value is 30 and the lowest value is 15.
Thus, the range of the data is given by
Range = Highest value - Lowest value
Range = 30 - 15 = 15
Thus, the range of the data is 15.
<u>Interquartile range:</u>
The interquartile range is the difference between the ends of the box in the box plot.
Thus, the interquartile range is given by
Interquartile range = 27 - 18 = 9
Thus, the interquartile range is 9.
Answer:
(C)
Step-by-step explanation:
20 for each day=20x
4 for hot dogs sold=4x
20x+4x
(C)
Hi.
Your answer is going to be
C.) 33
Hope this helps! :)
For question one:
First class goes from 8:00 to 9:00 second class starts 10 mins later at 9:10 and goes to 10:10. Ten minute break again 3rd class starts at 10:20, goes to 11:20. 10 min break again, fourth class starts 10 mins later at 11:30 and goes to 12:30. The answer for 1 is 12:30
The slope of the perpendicular line b is -1/7 if the slope of the perpendicular line a is 7.
According to the question,
Line 'a' is perpendicular to the line 'b'. If the slope of the line 'a' is 7.
The condition of slopes if two lines are perpendicular m₁ m₂ = -1
(7)(m₂) = -1
m₂ = -1/7
Hence, the slope of the perpendicular line b is -1/7 if the slope of the perpendicular line a is 7.
Learn more about perpendicular lines here
brainly.com/question/2505127
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