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ira [324]
2 years ago
15

WILL GIVE BRAINLIEST AND 20 POINTS! Which function is the inverse of f(x) = -5x -4?

Mathematics
2 answers:
inn [45]2 years ago
6 0

Answer:

-1/5x -4/5 = y

Step-by-step explanation:

f(x) = -5x -4

y = -5x-4

Switch x and y

x = -5y -4

Solve for y

Add 4

x+4 = -5y

Divide by -5

-1/5x - 4/5 = -5y/-5

-1/5x -4/5 = y

mr_godi [17]2 years ago
4 0

Answer:

f(x) = -5x - 4

let f(x)= y

y = -5x -4

x = -5y - 4

-5y = x+4

y = - (x +4)/5

The inverse of f(x) is -(x +4)/5

Hope this helps.

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How do I slove this eqaution, and whats the answer?<br> -3(n+6)+10=-9
Sauron [17]

Answer:

n = \frac{1}{3}

Step-by-step explanation:

  1. Apply the distributed property, so it now looks like this: -3n + -18 + 10 = -9
  2. Combine like terms: -3n + -8 = -9
  3. Simplify: -3n - 8 = -9
  4. Add 8 to each side, so it now looks like this: -3n = -1
  5. Divide each side by -3 to cancel out the -3 next to n. It should now look like this: n = 1/3

I hope this helps!

8 0
3 years ago
Find the length of the missing side х<br> 10.6<br> 8.6
Yanka [14]

Answer:

13.65

Step-by-step explanation:

5 0
2 years ago
Please prove this........​
Crazy boy [7]

Answer:  see proof below

<u>Step-by-step explanation:</u>

Given: A + B + C = π    →     C = π - (A + B)

                                    → sin C = sin(π - (A + B))       cos C = sin(π - (A + B))

                                    → sin C = sin (A + B)              cos C = - cos(A + B)

Use the following Sum to Product Identity:

sin A + sin B = 2 cos[(A + B)/2] · sin [(A - B)/2]

cos A + cos B = 2 cos[(A + B)/2] · cos [(A - B)/2]

Use the following Double Angle Identity:

sin 2A = 2 sin A · cos A

<u>Proof LHS → RHS</u>

LHS:                        (sin 2A + sin 2B) + sin 2C

\text{Sum to Product:}\qquad 2\sin\bigg(\dfrac{2A+2B}{2}\bigg)\cdot \cos \bigg(\dfrac{2A - 2B}{2}\bigg)-\sin 2C

\text{Double Angle:}\qquad 2\sin\bigg(\dfrac{2A+2B}{2}\bigg)\cdot \cos \bigg(\dfrac{2A - 2B}{2}\bigg)-2\sin C\cdot \cos C

\text{Simplify:}\qquad \qquad 2\sin (A + B)\cdot \cos (A - B)-2\sin C\cdot \cos C

\text{Given:}\qquad \qquad \quad 2\sin C\cdot \cos (A - B)+2\sin C\cdot \cos (A+B)

\text{Factor:}\qquad \qquad \qquad 2\sin C\cdot [\cos (A-B)+\cos (A+B)]

\text{Sum to Product:}\qquad 2\sin C\cdot 2\cos A\cdot \cos B

\text{Simplify:}\qquad \qquad 4\cos A\cdot \cos B \cdot \sin C

LHS = RHS: 4 cos A · cos B · sin C = 4 cos A · cos B · sin C    \checkmark

7 0
3 years ago
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Lorico [155]
14 my teacher just told me the answer
6 0
2 years ago
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Write out the following proportions in words. 81/9 = 45/5
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