Answer:
Option B.
Step-by-step explanation:
The given inequalities are


We need to find the ordered pair which makes both inequalities true.
Check the above inequalities for each given ordered pair.
For (-3,5),
(False)
For (-2,2),
(True)
(True)
So, both inequalities are true for (-2,2). Option B is correct.
For (-1,-3),
(False)
For (0,-1),
(False)
Both inequalities are not true for (-3,5), (-1,-3) and (0,-1).
Therefore, the correct option is B.
Answer:
the angles in squares and rectangles it's always 90° so two squares or two rectangles with same side lengths are congruent.
$52.50 / 42 = 1.25
$1.25 per each slice
Answer:
The answer is "
"
Step-by-step explanation:
Given:

Find critical points:

differentiate the value with respect of x:
critical points
![\to (x-e)^2 e^{(e-x)} [e+3-x]=0\\\\\to e^{(e-x)}\neq 0 \\\\\to (x-e)^2=0\\\\ \to [e+3-x]=0\\\\\to x=e\\\\\to x=e+3\\\\\to x= e,e+3](https://tex.z-dn.net/?f=%5Cto%20%28x-e%29%5E2%20e%5E%7B%28e-x%29%7D%20%5Be%2B3-x%5D%3D0%5C%5C%5C%5C%5Cto%20e%5E%7B%28e-x%29%7D%5Cneq%200%20%5C%5C%5C%5C%5Cto%20%28x-e%29%5E2%3D0%5C%5C%5C%5C%20%5Cto%20%5Be%2B3-x%5D%3D0%5C%5C%5C%5C%5Cto%20x%3De%5C%5C%5C%5C%5Cto%20x%3De%2B3%5C%5C%5C%5C%5Cto%20x%3D%20e%2Ce%2B3)
So,
The critical points of 
324 inches = 27 feet.
10 yards = 30 feet
30 - 27 = 3.
Final answer: 3 feet of fringe will be left over.
P.S, could you mark this the brainly answer? :)