Hey there! :)

The formula for finding volume of a cone : ( π · r² · h ) ÷ 3

Radius = 6
6² = 6 · 6 = 36

Height = 8

π = 3.14

Multiply:

8 × 6 × 3.14 = 150.72

The volume is 150.72 cubic meters

Hope this helps :)

6 0

3 years ago

PLEASE HELP ASAP

gayaneshka [121]

Answer:

<u>4 CD's cost $30.40, so one CD costs:</u>

4p = $30.40
p = $30.40/4
p = $7.60

80% of the regular price is $7.60

<u>If the regular price is r, we have:</u>

0.8r = $7.60
r = $7.60/0.8
r = $9.5

<u>3 CD's at regular price cost:</u>

$9.5*3 = $28.5

Since $25 < $28.5, we can't buy 3 more CD's.

See Part B

3 0

3 years ago

Given f'(x) = (x-4)(4-2x), find the x-coordinate for relative maximum on the graph of f(x)

antiseptic1488 [7]

Answer:

The coordinate of the relative maximum is x=4.

Step-by-step explanation:

Given that the derivative of the function $f(x)$ is $f'(x) = (x-4)(4-2x)$ , the maxima and minima or the critical points can be found where $f'(x)=0,$ that is:

$f'(x) = (x-4)(4-2x)=0.$

The solutions to this equation are $x=4$ and $x=2.$

Now, if the second derivative $f''(x)$ for a function $f(x)$ is negative at a critical point, then the critical point is the relative maximum.

Therefore we want to see at which of the two critical points is $f''(x)$ negative. The second derivative is:

$\frac{\mathrm{d f'(x)}}{\mathrm{d}x}=f''(x)=-4(x-3).$

Now $f''(4)$ is $-4$ , and $f''(2)$ is $+4$ , therefore we deduce that the relative maxium is located at $x=4$ , because there the second derivative $f''(x)$ is negative.

4 0

3 years ago