5-2=3 so therefore y=3
Remember to work backwards and use opposite operations.
Answer:
Given MC = 4
AN = 14
To Find, the length of NB
Step-by-step explanation:
AB is a line which has midpoint “C”. Now the line is divided into two equal portion AC and CB.
The AC has midpoint “M” and MC is 4, so AM will also be 4.
N is the midpoint of CB. So, CB = CN + NB
Now we know AC = AM + MC = 4 + 4 =8
Given, AN = 14
AN = AC + CN
14 = 8 + CN
CN = 6
Since N is the midpoint of CB then, CN = NB
Therefore, the NB is 6
Answer:
a = √11 and b = 6
Step-by-step explanation:
Refer to attached picture for reference
for an right triangle with angle θ
we are given
cos θ = 5/6 = length of adjacent side / length of hypotenuse
hence
adjacent length = 5 units
hypotenuse length = 6 units
the missing side is the "opposite" length which we can find with the Pythagorean equation. in our case:
hypotenuse ² = adjacent ² + opposite² (rearrange)
opposite ² = hypotenuse ² - adjacent ²
opposite ² = 6² - 5²
opposite = √ (6²-5²) = √11
sin θ = opposite length / hypotenuse (substitute values above)
sin θ = √11 / 6
hence a = √11 and b = 6
This is a difference of squares, meaning that when you multiply the binomials it would be the front term squared minus the last term squared.
The front term squared = (3A) squared = 9A squared
The last term squared = (4B) squared = 16B squared
Final Answer: D. 9A squared - 16B squared
Actually, this is not about angles. It's about the length of the sides in a right triangle.
In EVERY right triangle, the squares of the lengths of the short sides add up
to the square of the length of the longest side. You're in high school math,so
I'm SURE you've heard that in class before ... possibly even just before you
were assigned this problem.
Let's say that again: The squares of the lengths of the sides that meet at
the right angle add up to the square of the length of the longest side. In
the triangle in this particular problem, that means
a² + b² = c²
You know the lengths of 'b' and 'c', so you shouldn't have any trouble finding
the length of 'a'.
