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nadezda [96]
3 years ago
9

Fine the sun or different simplify the expression ( 3X +5 ) -( negative 4X + 1(

Mathematics
2 answers:
ohaa [14]3 years ago
8 0
13x u add parentheses since two negatives positive
Wewaii [24]3 years ago
7 0
<span>3X +5  -( negative 4X + 1)
=</span><span>3X +5  -( -4X + 1)
</span>=3X +5  + 4X -1
=7X+4
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On any given day, mail gets delivered by either Alice or Bob. If Alice delivers it, which happens with probability 1/4 , she doe
Troyanec [42]

Answer:

(a) The value of fₓ (9.5) is 0.125.

(b) The value of fₓ (10.5) is 0.50.

Step-by-step explanation:

Let <em>X</em> denote delivery time of the mail delivered by Alice and <em>Y</em> denote delivery time of the mail delivered by Bob.

It i provided that:

X\sim U(9, 11)\\Y\sim U(10, 12)

The probability that Alice delivers the mail is, <em>p</em> = 1/4.

The probability that Bob delivers the mail is, <em>q</em> = 3/4.

The probability density function of a Uniform distribution with parameters [<em>a</em>, <em>b</em>] is:

f(x)=\left \{ {{\frac{1}{b-a};\ a, b>0} \atop {0;\ otherwise}} \right.

The probability density function of the delivery time of Alice is:

f(X_{A})=\left \{ {{\frac{1}{b-a}=\frac{1}{2};\ [a, b]=[9, 11]} \atop {0;\ otherwise}} \right.

The probability density function of the delivery time of Bob is:

f(X_{B})=\left \{ {{\frac{1}{b-a}=\frac{1}{2};\ [a, b]=[10, 12]} \atop {0;\ otherwise}} \right.

(a)

Compute the value of fₓ (9.5) as follows:

For delivery time 9.5, only Alice can do the delivery because Bob delivers the mail in the time interval 10 to 12.

The value of fₓ (9.5) is:

f_{X}(9.5)=p.f(X_{A})+q.f(X_B})\\=(\frac{1}{4}\times \frac{1}{2})+(\frac{3}{4}\times0)\\=\frac{1}{8}\\=0.125

Thus, the value of fₓ (9.5) is 0.125.

(b)

Compute the value of fₓ (10.5) as follows:

For delivery time 10.5, both Alice and Bob can do the delivery because Alice's delivery time is in the interval 9 to 11 and that of Bob's is in the time interval 10 to 12.

The value of fₓ (10.5) is:

f_{X}(10.5)=p.f(X_{A})+q.f(X_B})\\=(\frac{1}{4}\times \frac{1}{2})+(\frac{3}{4}\times\frac{1}{2})\\=\frac{1}{8}+\frac{3}{8}\\=0.50

Thus, the value of fₓ (10.5) is 0.50.

5 0
3 years ago
You have decided to wallpaper your rectangular bedroom. the dimensions are 12 feet 6 inches by 10 feet 6 inches by 8 feet 0 inch
Papessa [141]
The wall area is the product of the room perimeter and the room height:
   A₁ = (2*(12.5 ft + 10.5 ft))*(8.0 ft) = 368 ft²

The window and door area together is
   A₂ = 2*((4 ft)*(3 ft)) + (7 ft)*(3 ft) = 45 ft²

The area of one roll of wallpaper is
   A₃ = (2.5 ft)*(30 ft) = 75 ft²

Then the number of rolls of wallpaper required will be
   1.1*(A₁ - A₂)/A₃ ≈ 4.74

5 rolls of wallpaper should be purchased.

_____
As a practical matter, not much of the window and door area can be saved. The rolls are 30 inches wide, but the openings are 36 inches wide. Some will likely have to be cut from two strips. The strips will have to be the full length of the wall, and the amount cut likely cannot be used elsewhere. If the window and door area cannot be salvaged, then likely ceiling(5.4) = 6 rolls will be needed (still allowing 10% for matching and waste).
8 0
3 years ago
Write the equation of the following line in slope-intercept form.
slega [8]

Answer:

y=2/5x+4 Answer: A)

Step-by-step explanation:

8 0
2 years ago
What is the value of x? <br> 64 68<br> (8x -12)<br> (2x + 18)
tamaranim1 [39]
(8x - 12) + 64 + 68 = 180
(A straight line equals to 180)
8x - 12 + 132 = 180
Combine liked terms
8x + 120 = 180
-120 on both sides
8x = 40
/8 on both sides
x = 5

(8x - 12)
8(5) - 12
40 - 12
28

(2x + 18)
2(5) + 18
10 + 18
28

Answer:
x = 5
4 0
3 years ago
Please help me with this question:<br> 6px3=3x6p= ____p
Ivanshal [37]

Answer:

   12

Step-by-step explanation:

It looks like you're given the equations ...

  6px^3 = 3x^6p

Dividing both sides by 3px^3, we get ...

 2 = x^3

Substituting that into the left side of the equation, we have ...

  6px^3 = 12p

It appears this is the expression you want on the right.

  6px^3 = 3x^6p = 12p

8 0
3 years ago
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