I need help with this plz.
2 answers:
<h3>Answers:</h3>
- T ' = (3,0)
- Q ' = (1, 0)
- M ' = (0,2)
- Y ' = (0,3)
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Explanation:
T = (0,0) moves to T ' = (3,0) since we shift 3 units to the right. We add 3 to the x coordinate. The y coordinate does not change since we're not shifting up or down.
Q = (-2,0) moves to Q ' = (1,0) after applying the same rule we did to point T.
M = (-3,2) moves to M ' = (0,2)
Y = (-3,3) moves to Y ' = (0,3)
See the diagram below
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Since a right triangle has special rules to it such that the hypotenuse squared equals the sum of the squares of the other 2 sides. In other words, if the hypotenuse = c, and the 2 smaller sides are a and b, then:
Solving for c (hypotenuse), we get:
Therefore c is the root of the square of the other sides. So by having root18, it's like saying:
Getting rid of the square root, so sides a and b must have their squares total 18:
the only squares < 18 are: 16 (4×4), 9 (3×3), 4 (2×2), and 1 (1×1)
of those above added in any order of two of them, only 16+4
I HOPE THAT IS ALONG THE LINE THAT WAS ASKED FOR!!! :-D
Solving for c (hypotenuse), we get:
Therefore c is the root of the square of the other sides. So by having root18, it's like saying:
Getting rid of the square root, so sides a and b must have their squares total 18:
the only squares < 18 are: 16 (4×4), 9 (3×3), 4 (2×2), and 1 (1×1)
of those above added in any order of two of them, only 16+4
I HOPE THAT IS ALONG THE LINE THAT WAS ASKED FOR!!! :-D
Answer:
A: -41/9
Step-by-step explanation:
Substitute the point (4, -5) and slope -1/9 into the equation y = mx + b.
-5 = -1/9(4) + b
-5 = -4/9 + b
Solve for b:
b = -41/9
Our equation: y = -1/9(x) - 41/9
