The triangle that forms is a right-angled triangle. To work out the area, you just do the base × height, all divided by 2.
Therefore, you do 5 (the base) × 4 (the height) and you get 20.
Then you divide by 2 to finish the equation and you should find that the total area of the triangle is 10 units² (20 ÷ 2 = 10).
Hope that helps :)
Solution:
we are given that
Inscribed angle
Intercepted arc
As we know that the Inscribed angle is Half of the measure of the intercepted arc.
So we can write

Answer:
D.
Step-by-step explanation:
First, multiply straight across and put everything together:

Notice we can simplify by cancelling a b and reducing 3/12:

This cannot be simplified further.
D.
Answer:
y² - (K- 2)y + 2k +1 = 0
equal roots means D=0
D= b^2 - 4ac
a=1, b= (k-2), c= 2k+1
so,
(k-2)^2 - 4(1)(2k+1) = 0
=> k^2 +4 - 8k -4 = 0
=> k^2 -8k = 0
=> k^2 = 8k
=> k= 8k/k
=> k = 8
Therefore the answer is k= 8
Hope it helps........