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2 years ago

What is an algebraic expression for the number of hours in "m" minutes

Mathematics

2 answers:

Svetlanka [38]2 years ago

7 0

60m = 1 hour
/60 /60

1m = 1/60 hours
xm xm

m = m/60

So, "m" minutes = m/60 hours

Ex: if m = 120: 120/60: 2 hours

Nikolay [14]2 years ago

5 0

M×4=8 Answer m=2 2×4=8

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Kramer Fabrications stockholders' equity at the beginning of July 2017 was $600,000. During the month, the company earned net in

Ymorist [56]

Answer:

$720,000

Step-by-step explanation:

As per the question,

Kramer Fabrications stockholders' equity at the beginning of July 2017

Stockholders' equity = $600,000

Net income earned = $145,000

Dividends paid = $25,000

Stockholders' equity at the end of of July 2017

= Net income - Dividend + Stockholders’ Equity

= $145,000 - $25,000 + $600,000

= $720,000

Therefore,

The amount of stockholders' equity at the end of of July 2017 = $720,000.

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3 years ago

A horse has a water barrel in which 3/10 of a gallon is drank out of it every day. How many days will it take the horse to drink

Troyanec [42]

Answer:

140 days

Step-by-step explanation:

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2 years ago

Read 2 more answers

Does anyone know what X equals to

Dmitrij [34]

Best Answer

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3 years ago

SSSSS [86.1K]

7. y = 1, AB = 1, BD = 10 and AD = 11

8. x = 5, AB = 20 and BC = 20

9. x= 5 and AB = 33

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2 years ago

A metallurgist has an alloy with 5% titanium and an alloy with 30% titanium. He needs 100 grams of an alloy with 15% titanium. H

andrey2020 [161]

Let us convert the percentages to decimal format first.. so 5% is just 5/100 or 0.05 and 15% is just 15/100 or 0.15

so hmmm, so, let's say it needs "x" amount and "y" amount of each respectively, so, whatever "x" and "y" are, they must add up to 100, and whatever their concentration is, must add up to what the mixture yields

thus

$\bf \begin{array}{lccclll}
&amount&concentration&
\begin{array}{llll}
concentrated\\
amount
\end{array}\\
&-----&-------&-------\\
\textit{5\% alloy}&x&0.05&0.05x\\
\textit{30\% alloy}&y&0.30&0.3y\\
-----&-----&-------&-------\\
mixture&100&0.15&15
\end{array}
\\\\\\
\begin{cases}
x+y=100\implies \boxed{y}=100-x\\
0.05x+0.3y=15\\
----------\\
0.5x+0.3\left( \boxed{100-x} \right)=15
\end{cases}$

solve for "x"

what's "y"? well, y = 100 - x

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3 years ago