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Helga [31]
3 years ago
7

What value of c makes the equation true?

Mathematics
1 answer:
8_murik_8 [283]3 years ago
3 0
Comparing forms, you see that
  4 = ∛c

The value of c is found by cubing both sides of this equation.
  4³ = c = 64
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If a desk is 36 inches how many feet is it there are 12 inches in a foot
Maksim231197 [3]
3 feet because 36 divided by 12 is 3
3 0
3 years ago
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In August 2003, 56% of employed adults in the United States reported that basic mathematical skills were critical or very import
Serga [27]

Answer:

Yes

Step-by-step explanation:

First, suppose that nothing has changed, and possibility p is still 0.56. It's our null hypothesis. Now, we've got Bernoulli distribution, but 30 is big enough to consider Gaussian distribution instead.

It has mean μ= np =  30×0.56=16.8

standard deviation s = √npq

sqrt(30×0.56×(1-0.56)) = 2.71

So 21 is (21-16.8)/2.71 = 1.5494 standard deviations above the mean. So the level increased with a ˜ 0.005 level of significance, and there is sufficient evidence.

7 0
3 years ago
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lesantik [10]
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4 0
3 years ago
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Wich graph is the result of the reflection f(x) =1/4(8)^x across the y axis and then across the x- axis
Snowcat [4.5K]

Answer:

I assume that the function is:

f(x) = \frac{1}{4}*8^x

Now let's describe the general transformations that we need to use in this problem.

Reflection across the x-axis:

For a general function f(x), a reflection across the x-axis is written as:

g(x) = -f(x)

Reflection across the y-axis:

For a general function f(x), a reflection across the y-axis is written as:

g(x) = f(-x)

Then a reflection across the y-axis, and then a reflection across the x-axis is just:

g(x) = -(f(-x)) = -f(-x)

In this case, we have:

f(x) = \frac{1}{4}*8^x

then:

g(x) = -f(-x) =  -\frac{1}{4}*8^{-x}

Now we can graph this, to get the graph you can see below:

6 0
3 years ago
5x + 10 = −4x − 17 what is x
meriva
5x + 10 = -4x - 17 
 +4x          +4x

5x + 4x = 9x

9x + 10 = -17
      -10     -10

-27

9x = -27        9x/9 = -27/9

x = -3
5 0
3 years ago
Read 2 more answers
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