Find the value of x to the nearest degree <br>a. 30<br>b. 60<br>c. 70<br>d. 85

X-y=0 and 5x-2y=6 solve by elimination

Elena-2011 [213]

Answer:

(2,2)

Step-by-step explanation:

first take x-y=0 and multiply it by -5 you will then get this

-5x+5y=0

5x-2y=6

add those together

3y=6

divide by 3

y=2

now plug 2 in for y

x-2=0

add 2 to both sides

x=2

6 0

2 years ago

Out of 400 applicants for a job, 179 are female and 72 are female and have a graduate degree. Step 2 of 2 : If 118 of the applic

Dafna11 [192]

Answer:

36/59 or 0.610

Step-by-step explanation:

P(female and degree)/P(degree)

72/118

36/59

0r 0.610

7 0

2 years ago

What is y greater then or equal to 2x on a graph

Juliette [100K]

Answer:

The minimal number for the objective function P =20x+16y is: 780

The value of x then is: 15

and the value of y then is : 30

Step-by-step explanation:

We are given a system of inequalities as:

y is less than or equal to 2x

i.e. y ≤ 2x--------(1)

x + y is greater than or equal to 45

i.e. x+y ≥ 45 ------------(2)

and x is less than or equal to 30.

i.e. x ≤ 30 -----------(3)

On plotting these inequalities we get the boundary points as:

(15,30) , (30,60) and (30,15)

( Since, the optimal solution always exist at the boundary point )

The optimal function is given by:

Minimize P = 20x+16y

Hence, at (15,30) we get:

P= 780

at (30,60) we get:

P= 1560

at (30,15) we get:

P= 840

This means that the minimal value of the function is 780

and the value exist at (15,30)

5 0

3 years ago

PLEASE HELP NEED THIS TO PASS

yaroslaw [1]

The solutions to f(x) = 64 is x = 7 and x = –7.

Solution:

Given data:

$$f(x)=x^{2}+15$ – – – – (1)

$f(x)=64$ – – – – (2)

To find the solutions to f(x) = 64.

Equate equation (1) and (2), we get

$x^2+15=64$

Subtract 15 from both sides of the equation.

$x^2+15-15=64-15$

$x^2=49$

$x^2=7^2$

Taking square root on both sides of the equation, we get

x = ±7

The solutions to f(x) = 64 is x = 7 and x = –7.

5 0

3 years ago

A circle has a diameter of 12 units, and its center lies on the x-axis. What could be the equation of the circle?

ycow [4]

Answer:

$x^{2} +y^{2} =36$

Step-by-step explanation:

A circle centered at (0,0) with radius r is $x^{2} +y^{2} =r^{2}$

Since your circle has diameter of 12, then its radius is 6. Then $r^{2} =36$

So a possible answer is: $x^{2} +y^{2} =36$

If you want to move the location of the center, but keep it on the x-axis, then add or subtract a number to the x, such as this:

$(x+4)^{2} +y^{2} =36$

The center of this circle would be (-4, 0) which is still on the x-axis.

8 0

2 years ago

Find the value of x to the nearest degree a. 30b. 60c. 70d. 85