Question

In ΔOPQ, m∠O = (3x+12)^{\circ}(3x+12)

Answer 1

Answer:

The measure of angle P is 80 degrees

Step-by-step explanation:

we know that

The sum of the interior angles in a  triangle must be equal to 180 degrees

In this problem we have that

$m\angle O+m\angle P+m\angle Q=180^o$

substitute the given values

$(3x+12)^o+(4x+4)^o+(x+12)^o=180^o$

solve for x

$(8x+28)=180$

$8x=180-28$

$8x=152$

$x=19$

Find the measure of angle P

$m\angle P=(4x+4)^o$

substitute the value of x

$m\angle P=(4(19)+4)=80^o$