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3 years ago

How do I solve for x ?X +8=-15

Mathematics

2 answers:

DanielleElmas [232]3 years ago

7 0

Subtract 8 from both sides
So you end up with x = -23

slavikrds [6]3 years ago

4 0

Solve for x; in order to do that you must subtract 8 from both sides so x is by itself; the answer is -23

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Answer:

14 lessons.

Step-by-step explanation:

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2 years ago

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A pathway divides a rectangular garden into two parts as shown. Find the measure of angle A

frosja888 [35]

Answer:

m < A = 101 degrees.

Step-by-step explanation:

The transverse line crosses 2 parallel lines (opposite angles of a rectangle are parallel) , so the same side angles add up to 180 degrees.

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2 years ago

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Find the circumference of a circle whose.<br> A. Diameter is 14cm<br> B. Radius is 3.5cm

Nikitich [7]

Hello!

Circumference of a Circle

C=πd

C=2πr

Plug in the values

C=14π

C≈44 cm

C=2π×3.5

C≈22 cm

Hope everything is clear.

Let me know if you have any questions!
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5 0

2 years ago

Find the roots of h(t) = (139kt)^2 − 69t + 80

Sonbull [250]

Answer:

The positive value of $k$ will result in exactly one real root is approximately 0.028.

Step-by-step explanation:

Let $h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ , roots are those values of $t$ so that $h(t) = 0$ . That is:

$19321\cdot k^{2}\cdot t^{2}-69\cdot t + 80=0$ (1)

Roots are determined analytically by the Quadratic Formula:

$t = \frac{69\pm \sqrt{4761-6182720\cdot k^{2} }}{38642}$

$t = \frac{69}{38642} \pm \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$

The smaller root is $t = \frac{69}{38642} - \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ , and the larger root is $t = \frac{69}{38642} + \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ .

$h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ has one real root when $\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} = 0$ . Then, we solve the discriminant for $k$ :

$\frac{80\cdot k^{2}}{19321} = \frac{4761}{1493204164}$

$k \approx \pm 0.028$

The positive value of $k$ will result in exactly one real root is approximately 0.028.

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2 years ago

Is PQR = STU? if so, name which similarity postulate or theorem applies.

lutik1710 [3]

Answer:

Step-by-step explanation:

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3 years ago