m=90
hope i helped! (sorry if wrong)
HOW TO SOLVE:
1) use x as a variable
2) the starting equation is:
4x + 3x + 5x = 18
3) add all the like terms on the left side of the equation:
12x = 18
4) Divide by 12 on both sides:
x=1.5
5) Find the lengths of the sides:
- 4x = 4(1.5) = 6
- 3x = 3(1.5) = 4.5
- 5x = 5(1.5) = 7.5
SO, the lengths of the sides of this triangle are: 6, 4.5, and 7.5
For large sample confidence intervals about the mean you have:
xBar ± z * sx / sqrt(n)
where xBar is the sample mean z is the zscore for having α% of the data in the tails, i.e., P( |Z| > z) = α sx is the sample standard deviation n is the sample size
We need only to concern ourselves with the error term of the CI, In order to find the sample size needed for a confidence interval of a given size.
z * sx / sqrt(n) = width.
so the z-score for the confidence interval of .98 is the value of z such that 0.01 is in each tail of the distribution. z = 2.326348
The equation we need to solve is:
z * sx / sqrt(n) = width
n = (z * sx / width) ^ 2.
n = ( 2.326348 * 6 / 3 ) ^ 2
n = 21.64758
Since n must be integer valued we need to take the ceiling of this solution.
n = 22
Answer:
you can do it , you can solve it , if you will not learn no job no money so need to study :))
Step-by-step explanation:
hope it helps ;)))
Answer:
It's 540.
Step-by-step explanation:
You divide 9 by 21 then you multiply it by 1260 and you get 540
