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Tanya [424]
3 years ago
8

Leslie has a voucher worth $5 coupon from Wal-Mart.She visits the store and purchases a wallet that amounted to double the price

she paid for the groceries she bought.If Leslie was billed for a total of $34.45 after the voucher was redeemed, what was the cost of the wallet?
Mathematics
1 answer:
jasenka [17]3 years ago
6 0

Answer:

The Cost of wallet was $26.30.

Step-by-step explanation:

Given:

Total billed after redeeming voucher = $34.45

Voucher worth = $5

We need to find the cost of Wallet.

Solution:

Let the amount paid for groceries be 'x'.

Now Given:

She purchases a wallet that amounted to double the price she paid for the groceries she bought.

Cost of wallet = 2x

Now to find the cost of wallet we will consider the amount before redeeming the voucher.

Hence Total bill before redeeming the voucher = \$34.45+\$5=\$39.45

Now We can say that;

Total bill is equal to sum of Cost of wallet and Cost of groceries.

framing in equation form we get;

x+2x=39.45\\\\3x=39.45

Dividing both side by 3 we get;

\frac{3x}{3}=\frac{39.45}{3}\\\\x=\$13.15

Cost paid for groceries = $13.15

Cost paid for wallet = 2x=2\times 13.15 =\$26.30

Hence the Cost of wallet was $26.30.

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Answer:

Step-by-step explanation:

Note: I will leave the answers as fraction and in terms of pi unless the question states rounding conditions to ensure maximum precision.

From the question, we can tell it is a inversed-cone (upside down)

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We will now find the volume of the cone.

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We know the density of ice is 0.93 grams per 1cm^{3}

1cm^{3} =0.93g\\\frac{168175\pi }{24}  cm^{3} =0.93(\frac{168175\pi }{24} )\\= 20473 g(Nearest Gram)

b) After 1 hour, we know that the new radius = 7.75cm - 0.35cm = 7.4cm

and the new length, h = 350cm - 15cm = 335cm

Now we will find the volume of this newly-shaped cone.

Volume of cone = \pi (7.4)^{2} \frac{335}{3} \\= \frac{91723\pi }{15} cm^{3}

Volume of cone being melted = New Volume - Original volume

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c) Lets take the bucket as a round cylinder.

Given radius of bucket, r = 12.5cm (Half of Diameter) and h , height = 30cm.

Volume of cylinder = \pi r^{2} h\\=\pi (12.5)^{2} (30)\\=\frac{9375\pi }{2} cm^{3}

To overflow the bucket, the volume of ice melted must be more than the bucket volume.

Volume of ice melted after 5 hours = 5(\frac{35697\pi }{40} )\\=\frac{35697\pi }{8} cm^{3}

See, from here of course you are unable to tell whether the bucket will overflow as all are in fractions, but fret not, we can just find the difference.

Volume of bucket - Volume of ice melted after 5 hours

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from we can see the bucket can still hold more melted ice even after 5 hours therefore it will not overflow.

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