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grandymaker [24]
3 years ago
7

Will the product of -3x^3 + 2x - 4 and x^3+ x - 2 be the same as the product of x^3 +

Mathematics
1 answer:
Sophie [7]3 years ago
4 0
Blah blah blah I do not know find it on google hahaha lame
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100 multiply by 600 + 1000000=​
Slav-nsk [51]

Answer:

1060000

Step-by-step explanation:

just calculation does the job

6 0
3 years ago
Read 2 more answers
Pedmas
baherus [9]

Answer:

Step-by-step explanation:

You do what's in the innermost brackets first, unless you have an unknown variable.

6 0
3 years ago
It takes approximately 4.65 quarts of milk to make a pound of cheese. Express this amount as a mixed number in simplest form.
ikadub [295]
The correct answer would be 4 and 13/20
4 0
3 years ago
Allison bought jelly beans to share with her friends. She bought pounds of blueberry jelly beans and pounds of lemon jelly beans
Vaselesa [24]

Answer: 1\dfrac{11}{12}\text{ pounds}

Step-by-step explanation:

The complete question is provided in the attachment.

Given, Amount blueberry jelly beans= 1\dfrac{1}{4} pounds

=\dfrac{5}{4} pounds.

Amount lemon jelly beans = 2\dfrac{1}{3}pounds

=\dfrac{7}{2} pounds

Total jelly beans she bought = Amount blueberry jelly beans + Amount lemon jelly beans

=(\dfrac{5}{4}+\dfrac{7}{3}) pounds

=\frac{15+28}{12}\text{ pounds}\\\\=\dfrac{43}{12}\text{ pounds}

Amount of jelly beans she gave away = 1\dfrac{2}{3}=\dfrac{5}{3}\text{ pounds}

Amount of jelly beans she has left= Total jelly beans - Amount of jelly beans she gave away

=\dfrac{43}{12}-\dfrac{5}{3}\\\\=\dfrac{43-20}{12}\\\\=\dfrac{23}{12}\\\\=1\dfrac{11}{12}\text{ pounds}

She has left 1\dfrac{11}{12}\text{ pounds} of jelly beans.

6 0
3 years ago
Use a proportion to estimate each population. (Please solve both questions, thank you) (I’ll reward you with brainliest :)
hammer [34]

Answer:

<em>Step-by-step explanation:</em>

<em>Step 1. (The capture) Capture a sample  total counted =958, and them back tagged counted=38,total tagged=56 </em>

<em>The idea is to estimate the proportion p = m/N of tagged =102. </em>

<em>Step 2. (The recapture) After everything has settled down, capture a new sample of n fish. Count the number of tagged fish. Suppose that k of them are tagged. </em>

<em>It is reasonable that, k/n would be a good estimante for p = m/N. </em>

<em>Accordingly, for an estimate N of N, se solve the equation m/N= k/n. </em>

7 0
3 years ago
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