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allsm [11]
2 years ago
7

Allison bought jelly beans to share with her friends. She bought pounds of blueberry jelly beans and pounds of lemon jelly beans

. If she gave pounds of jelly beans away to her friends, how many pounds of jelly beans does Allison have left?

Mathematics
1 answer:
Vaselesa [24]2 years ago
6 0

Answer: 1\dfrac{11}{12}\text{ pounds}

Step-by-step explanation:

The complete question is provided in the attachment.

Given, Amount blueberry jelly beans= 1\dfrac{1}{4} pounds

=\dfrac{5}{4} pounds.

Amount lemon jelly beans = 2\dfrac{1}{3}pounds

=\dfrac{7}{2} pounds

Total jelly beans she bought = Amount blueberry jelly beans + Amount lemon jelly beans

=(\dfrac{5}{4}+\dfrac{7}{3}) pounds

=\frac{15+28}{12}\text{ pounds}\\\\=\dfrac{43}{12}\text{ pounds}

Amount of jelly beans she gave away = 1\dfrac{2}{3}=\dfrac{5}{3}\text{ pounds}

Amount of jelly beans she has left= Total jelly beans - Amount of jelly beans she gave away

=\dfrac{43}{12}-\dfrac{5}{3}\\\\=\dfrac{43-20}{12}\\\\=\dfrac{23}{12}\\\\=1\dfrac{11}{12}\text{ pounds}

She has left 1\dfrac{11}{12}\text{ pounds} of jelly beans.

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Answer:

1) Subtracting one from the other

2) x = 0.375 and y = 0.125

Step-by-step explanation:

Equation 1 :

\frac{2x+1}{2y}=7\\\\

Equation 2:

\frac{6x-1}{2y}=5

To solve these equations by the Elimination method we multiply equation 1 with 6 and multiply equation 2 with 2 so now,

\frac{2x+1}{2y} =7\\\\2x+1=14y\\\\Multiplying\ Equation\ 1\  with\ 6\\\\12x+6=84y

Now for the second equation:

\frac{6x-1}{2y}=5\\\\6x-1=10y\\\\Multiplying\ equation\ 2\ with\ 2 \\\\12x-2=20y

Now subtracting equation 2 from equation 1

12x+6=84y\\\\12x-2=20y\\\\Subtracting\ leads\ to\\12x-12x+6-(-2)=84y-20y\\0+8=64y\\8=64y\\8/64=y\\0.125=y

now insert this value of y into any equation

lets insert it into equation 1

\frac{2x+1}{2y} =7\\\\2x+1=14y\\2x+1=14(0.125)\\2x+1=1.75\\2x=1.75-1\\2x=0.75\\x=0.75/2\\x-0.375

5 0
3 years ago
Which does not represent an integer?
miv72 [106K]

Answer:

The answer is D

Step-by-step explanation:

  • Let's see all choices in detail

A . 0 it is correct because 0 is an integer

B .It seems like rational number but it is not simplified yet so -18 \ 2= -9

C .

\sqrt{9}  = 3 \: so \: it \: is \: also \: integer

D . 4\5 it is decimal so it is rational number not integer

I hope u like it

4 0
3 years ago
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Marat540 [252]

Answer:

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Step-by-step explanation:

Given

x^2 - 5x - 7 = 0

Required

Solve for x using:

x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}

First, we need to identify a, b and c

The general form of a quadratic equation is:

ax^2 + bx + c = 0

So, by comparison with x^2 - 5x - 7 = 0

a = 1     b = -5      c = -7

Substitute these values of a, b and c in

x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}

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Split the expression to two

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To solve further in decimal form, we have

x = \frac{5 + 7.28}{2}  or  x = \frac{5 - 7.28}{2}

x = \frac{12.28}{2}  or  x = \frac{-2.28}{2}

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3 years ago
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pishuonlain [190]

Answer:

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Step-by-step explanation:

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2 years ago
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