Let's do this by Briot-Ruffini
First: Find the monomial root
x - 2 = 0
x = 2
Second: Allign this root with all the other coeficients from equation
Equation = -3x³ - 2x² - x - 2
Coeficients = -3, -2, -1, -2
2 | -3 -2 -1 -2
Copy the first coeficient
2 | -3 -2 -1 -2
-3
Multiply him by the root and sum with the next coeficient
2.(-3) = -6
-6 + (-2) = -8
2 | -3 -2 -1 -2
-3 -8
Do the same
2.(-8) = -16
-16 + (-1) = -17
2 | -3 -2 -1 -2
-3 -8 -17
The same,
2.(-17) = -34
-34 + (-2) = -36
2 | -3 -2 -1 -2
-3 -8 -17 -36
Now you just need to put the "x" after all these numbers with one exponent less, see
2 | -3x³ - 2x² - 1x - 2
-3x² - 8x - 17 -36
You may be asking what exponent -36 should be, and I say:
None or the monomial. He's like the rest of this division, so you can say:
(-3x³ - 2x² - x - 2)/(x - 2) = -3x² - 8x - 17 with rest -36 or you can say:
(-3x³ - 2x² - x - 2)/(x - 2) = -3x² - 8x - 17 - 36/(x - 2)
Just divide the rest by the monomial.
I’m not really sure it’s really complicated
Answer:
y = 23/3
Step-by-step explanation:
Simplify both sides of equation
7 = y + -2/3
Flip equation
y + -2/3 = 7
Add 2/3 to both sides
y + -2/3 + 2/3 = 7 + 2/3
y = 23/3
Answer:
c
Step-by-step explanation:
Answer:
<em>The probability of scoring two goals in both times is</em><em> 0.137 or 13.7%</em>
Step-by-step explanation:
Statistics show that a certain soccer player has a 63% chance of missing the goal each time he shoots.
So 
Hence, the probability of getting success in his shoots will be,
The probability of scoring two goals in both times is,
