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2 years ago

Here are the first five terms of an arithmetic sequence.

Mathematics

2 answers:

Likurg_2 [28]2 years ago

7 0

33-7n is the required expression.

Have a nice day!!

charle [14.2K]2 years ago

5 0

Answer:

the answer is -7n+ 33

Step-by-step explanation:

i usually just add the constant difference to the first term to create the last value . it sometimes doesnt work but does most times

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How many dollars are in 65536

mezya [45]

65 thousand 5 hundred and thirty six dollars

4 0

3 years ago

I need help, I will put as brainiest 15 points. pls help

lidiya [134]

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Answer: 382.5

Explanation:

450 x .85 = 382.5

I hope this helped!

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2 years ago

a stockbroker charges customers $30 to open an account and $15 per month to manage the account. write an equation to represent t

Andreyy89

30+15n=360 would be your answer

3 0

3 years ago

I’m trying one last time

kap26 [50]

Answer:

The equation =3 is equivalent to = 0 +3. From this form, we know the line has slope =0.

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Find the length of midsegment YZ in trapezoid ABCD when A(-5,-6) B(-6,-2) C(-4,0) and D(3,2)

Luda [366]

Answer:

Option C

Step-by-step explanation:

Since, Y and Z are the midpoints of sides AB and CD of the given trapezoid.

Segment YZ will the midsegment of trapezoid ABCD.

By the theorem of midsegment,

m(YZ) = $\frac{1}{2}(AD+BC)$

By using expression for the length of a segment between two points,

Length of a segment = $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Distance between two points A(-5, -6) and D(3, 2),

AD = $\sqrt{(3+5)^2+(2+6)^2}$

AD = $\sqrt{64+64}$

AD = $\sqrt{128}$

AD = $8\sqrt{2}$

Distance between B(-6, -2) and C(-4, 0)

BC = $\sqrt{(-6+4)^2+(-2-0)^2}$

BC = $\sqrt{8}$

BC = $2\sqrt{2}$

Therefore, m(YZ) = $\frac{1}{2}(8\sqrt{2}+2\sqrt{2})$

= $\frac{1}{2} (10\sqrt{2})$

= $5\sqrt{2}$

Option C will be the answer.

7 0

2 years ago