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3 years ago

PLEASE HELL ASAP I BEED SOMEBODYS HELPPPPPPPPPPPPP

Mathematics

2 answers:

Nimfa-mama [501]3 years ago

5 0

<h3>Answer: Choice A) They are the only values that make both equations true</h3>

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Explanation:

plug x = 1.5 and y = -1.5 into the first equation

-2y + 6x = 12

-2(-1.5) + 6(1.5) = 12

3 + 9 = 12

12 = 12 ... we get a true equation

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Plug x = 1.5 and y = -1.5 into the second equation

4x + 12y = -12

4(1.5) + 12(-1.5) = -12

6 - 18 = -12

-12 = -12 ... another true equation

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Both equations are true when (x,y) = (1.5, -1.5)

So it is a solution of the system.

This is the only solution. This is because there is only one point of intersection of the two lines.

Illusion [34]3 years ago

3 0

your answer is part A ....

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Someone please help meeeee

zepelin [54]

Answer:

The number is -1

Step-by-step explanation:

The equation for the first part is (2n+7)2. This is because "twice a number" is 2n and "7 is added" will make it 2n+7. The "sum is multiplied by two" Is multiplying everything by two. This will make it (2n+7)

The second part is -8n+2. Since a number is multiplied by negative eight it will be -8n. Then it is added by two.

Both equation equal each other the overall equation will be (2n+7)2=-8n+2

You will distribute. making it 4n+14=-8n+2

Add 8n to both sides making it 12n+14=2

subtract 14 from both sides making it 12n=-12

Divide both sides by 12 . making it number=-1

4 0

3 years ago

Can someone answer this easy question 46 plus what equals 77

Reika [66]

Answer:

Step-by-step explanation:

46+x=77 subtract 46 from both sides

x=31

4 0

3 years ago

A clothing store offers a free T- shirt when a customer spends $75 or more. Lyndon has already spent $36.95 which statement best

Anna [14]

$38.05 or more because you need a minimum of $38.10

8 0

3 years ago

Shikha has quiz scores of 27, 25, 24, 26 and 25 this term. If she gets a score of 25 and 28, which part of the data( mean, media

forsale [732]

Answer:

mean and range

arrangement before: 24,25,25,26,27

arrangement after: 24,25,25,25,26,27,28

mean before: (27+25+24+26+25)/5 = 25.4

mean after: (27+25+24+26+25+25+28))/5 = 25.7

median before: 25

median after: 25

mode before: 25

mode after: 25

range before: 24 to 27

range after: 24 to 28

hence, the mean and range were affected while the median and mode remained unchanged.

7 0

2 years ago

Solve the following equations.<br> log2(x^2 − 16) − log^2(x − 4) = 1

Alenkasestr [34]

Answer:

$x=\frac{4*(2+e)}{e-2}$

Step-by-step explanation:

Let's rewrite the left side keeping in mind the next propierties:

$log(\frac{1}{x} )=-log(x)$

$log(x*y)=log(x)+log(y)$

Therefore:

$log(2*(x^{2} -16))+log(\frac{1}{(x-4)^{2} })=1\\ log(\frac{2*(x^{2} -16)}{(x-4)^{2}})=1$

Now, cancel logarithms by taking exp of both sides:

$e^{log(\frac{2*(x^{2} -16)}{(x-4)^{2}})} =e^{1} \\\frac{2*(x^{2} -16)}{(x-4)^{2}}=e$

Multiply both sides by $(x-4)^{2}$ and using distributive propierty:

$2x^{2} -32=16e-8ex+ex^{2}$

Substract $16e-8ex+ex^{2}$ from both sides and factoring:

$-(x-4)*(-8-4e-2x+ex)=0$

Multiply both sides by -1:

$(x-4)*(-8-4e-2x+ex)=0$

Split into two equations:

$x-4=0\hspace{3}or\hspace{3}-8-4e-2x+ex=0$

Solving for $x-4=0$

Add 4 to both sides:

$x=4$

Solving for $-8-4e-2x+ex=0$

Collect in terms of x and add $4e+8$ to both sides:

$x(e-2)=4e+8$

Divide both sides by e-2:

$x=\frac{4*(2+e)}{e-2}$

The solutions are:

$x=4\hspace{3}or\hspace{3}x=\frac{4*(2+e)}{e-2}$

If we evaluate x=4 in the original equation:

$log(0)-log(0)=1$

This is an absurd because log (x) is undefined for $x\leq 0$

If we evaluate $x=\frac{4*(2+e)}{e-2}$ in the original equation:

$log(2*((\frac{4e+8}{e-2})^2-16))-log((\frac{4e+8}{e-2}-4)^2)=1$

Which is correct, therefore the solution is:

$x=\frac{4*(2+e)}{e-2}$

6 0

3 years ago