<span>C. .25 i hope this helps</span>
Answer:
Probability of having two hits in the same region = 0.178
mu: average number of hits per region
x: number of hits
e: mathematical constant approximately equal to 2.71828.
Step-by-step explanation:
We can describe the probability of k events with the Poisson distribution, expressed as:

Being μ the expected rate of events.
If 535 bombs hit 553 regions, the expected rate of bombs per region (the events for this question) is:

For a region to being hit by two bombs, it has a probability of:

Answer:
8.6%
Step-by-step explanation:
To find the percent change, you will need to compute the positive difference and then divide the difference by the original (the older amount).
So the positive difference will be obtain by doing larger minus smaller:
6300
- 5800
-----------
500
The older amount was 5800.
So 500/5800 is the answer as a un-reduced fraction.
I'm going to reduce it by dividing top and bottom by 100:
500/5800 = 5/58
5/58 is the answer as a reduced fraction.
5 divided by 58 gives=0.086206897 in the calculator .
Approximately 0.0862 is the answer as a decimal.
To convert this to a percentage, multiply it by a 100:
8.62%
Rounded to the nearest tenths is 8.6%
-------------
So 5800+5800(.0862) should be pretty close to 6300 (not exactly though since we rounded).
5800+5800(.0862)=6299.96 using the calculator.
Y= -5.8 is the correct answer
Answer:1/3
Step-by-step explanation:
3-2 2/3 its easy because if you have 3 wholes and then only 2 2/3 of that is being taken away then you have 1/3 of 3 left over