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velikii [3]
3 years ago
10

Which of the following inequalities is graphed below? 

Mathematics
2 answers:
mestny [16]3 years ago
8 0
C



...................

lorasvet [3.4K]3 years ago
6 0
C.. y is less then or equal to -2x-2
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9d - 5 = 4d + 35<br> find what d equals.
Debora [2.8K]
9d - 5 = 4d + 35

9d (-4d) - 5 (+5) = 4d (-4d) + 35 (+5)

5d = 40

5d/5 = 40/5

d = 8

hope this helps
3 0
3 years ago
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A line passes through the points (1, 4) and (3,-4). Which is the equation of the line?
andrew-mc [135]

Answer:

Y=-4x+8

Step-by-step explanation:

3 0
3 years ago
What's <br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B50%20-%201%7D%20" id="TexFormula1" title=" \sqrt{50 - 1} " alt=" \sqrt
nikklg [1K]
Inside the root is 50-1

50-1 = 49

You would remain with root 49 but, if you calculate the square root the answer would be 7 because...

7•7 = 49


^ So, the answer is 7



4 0
3 years ago
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The diagram shows 3 ships A, B and C at sea.
Wittaler [7]

Answer:

5km + 4.5km +2.7km = 12.3km

5 0
2 years ago
Assume that the radius r of a sphere is expanding at a rate of 40 cm/min. The volume of a sphere is V = 4 3 πr3 and its surface
Scrat [10]

Answer:

The rate of change in surface area when r = 20 cm is 20,106.19 cm²/min.

Step-by-step explanation:

The area of a sphere is given by the following formula:

A = 4\pi r^{2}

In which A is the area, measured in cm², and r is the radius, measured in cm.

Assume that the radius r of a sphere is expanding at a rate of 40 cm/min.

This means that \frac{dr}{dt} = 40

Determine the rate of change in surface area when r = 20 cm.

This is \frac{dA}{dt} when r = 20. So

A = 4\pi r^{2}

Applying implicit differentiation.

We have two variables, A and r, so:

\frac{dA}{dt} = 8r\pi \frac{dr}{dt}

\frac{dA}{dt} = 8*20\pi*40

\frac{dA}{dt} = 20106.19

The rate of change in surface area when r = 20 cm is 20,106.19 cm²/min.

6 0
3 years ago
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