Answer:
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Answer:
The second term of the sequence is 8 False ⇒ B
The third term of the sequence is 3 True ⇒ A
The fourth term of the sequence is -3 True ⇒ A
Step-by-step explanation:
The form of the recursive rule is:
f(1) = first term; f(n) = f(n - 1) + d, where
- f(n - 1) is the term before the nth term
- d is the common difference
∵ f(1) = 15, f(n) = f(n - 1) - 6 for n ≥ 2
∴ The first term = 15
∴ d = -6
let us find the 2nd, 3rd, and 4th terms
∵ n = 2
∴ f(2) = f(1) - 6
∵ f(1) = 15
∴ f(2) = 15 - 6 = 9
∴ The second term is 9
∴ The second term of the sequence is 8 False
∵ n = 3
∴ f(3) = f(2) - 6
∵ f(2) = 9
∴ f(3) = 9 - 6 = 3
∴ The third term is 3
∴ The third term of the sequence is 3 True
∵ n = 4
∴ f(4) = f(3) - 6
∵ f(3) = 3
∴ f(4) = 3 - 6 = -3
∴ The fourth term is -3
∴ The fourth term of the sequence is -3 True
Answer:
3/5 or 0.6
Step-by-step explanation:
Here, given the value of tan theta , we want to find the value of sine theta
Mathematically;
tan theta = 0pposite/adjacent
Sine theta = opposite/hypotenuse
Firstly we need the length of the hypotenuse
This can be obtained using the Pythagoras’ theorem which states that the square of the hypotenuse equals sum of the squares of the two other sides.
Let’s call the hypotenuse h
h^2 = 3^2 + 4^2
h^2 = 9 + 16
h^2 = 25
h = √(25)
h = 5
Now from the tan theta, we know that the opposite is 3
Thus, the value of the sine theta = 3/5 or simply 0.6
Rational are number that dont repeat and you can make it into a fraction
irrational are numbers that go on forever and never stop
