Answer:
Step-by-step explanation:
Let x be the number.
Sum of five and 8 times a number: 8x + 5
Fifty plus one half of the number: 50 + (1/2)x

This would practically be very reliable of course. We can see in the sentence above that y and x, and x and y are both depending on each other. So, now that this has been considered, we can see that whenever "x" would be a certain number, this would show you that "y" would also be a certain number, and depending how much "x" or "y" would move, it would also change these variable no matter how they move.
This would be a matter of division. As we can see above on how 9 and 15 could be divisible down the line as they multiply.
Therefore, we would then see how many times would "x" which is 9, how many times that would go in 33.
Let's start!

We take this "3.6" away from this, and we would plug it into "y".
We then do the following:

Therefore, when "x" = 33, "y" would then equal 55.
Your answer:
Answer:
The length is 20
The width is 12
Step-by-step explanation:
Please let me know if you want me to add an explanation as to why this is the answer. I can definitely do that, I just wouldn’t want to write it if you don’t want me to :)
Answer:
MOnkey mode
Step-by-step explanation:
cause why not
Simplify the following:
3 x^2 (3 x - 6/x)
Put each term in 3 x - 6/x over the common denominator x: 3 x - 6/x = (3 x^2)/x - 6/x:
3 x^2 (3 x^2)/x - 6/x
(3 x^2)/x - 6/x = (3 x^2 - 6)/x:
3 x^2 (3 x^2 - 6)/x
Combine powers. (3 x^2 (3 x^2 - 6))/x = 3 x^(2 - 1) (3 x^2 - 6):
3 x^(2 - 1) (3 x^2 - 6)
2 - 1 = 1:
3 x (3 x^2 - 6)
Factor 3 out of 3 x^2 - 6:
3 x×3 (x^2 - 2)
3×3 = 9:
Answer: 9 x (x^2 - 2)