Question

What is the midpoint of AB?

Answer 1

Answer:

The midpoint of AB is (0.5,1).

Step-by-step explanation:

From the given graph it is clear that the vertices of the triangle ABC are A(-2,5), B(3,-3) and C(-4,-1).

If end points of a line segment are $(x_1,y_1)$ and $(x_2,y_2)$, then the midpoint of that segment is

$Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

We need to find the midpoint of AB.

$Midpoint=(\frac{-2+3}{2},\frac{5+(-3)}{2})$

$Midpoint=(\frac{1}{2},\frac{5-3}{2})$

On further simplification we get

$Midpoint=(\frac{1}{2},\frac{2}{2})$

$Midpoint=(0.5,1)$

Therefore the midpoint of AB is (0.5,1).

Answer 2

The formula of a midpoint:

$\left(\dfrac{x_A+x_B}{2},\ \dfrac{y_A+y_B}{2}\right)$

We have

$A(-2,\ 5),\ B(3,\ -3)$

Substitute:

$\dfrac{-2+3}{2}=\dfrac{1}{2}=0.5\\\\\dfrac{5+(-3)}{2}=\dfrac{2}{2}=1$

Answer: (0.5, 1).