Answer:
Jacqueline runs at 6.25 minutes per mile
Step-by-step explanation:
Here we have that the total training time for Jacqueline = 54 minutes
The time for which Jacqueline swims = 30 minutes
Therefore, the time in which Jacqueline runs = 54 min. - 30 min. = 20 minutes
Therefore the equation for Jacqueline's speed = Distance/Time we have
Jacqueline's pace = 3.2 miles/20 minutes = 0.16 miles/minute
Therefore Jacqueline's pace = 0.16 miles/minute
The equation for Jacqueline's pace in miles/minute is presented as follows
Jacqueline's pace in miles/minute = Time of running/Distance
Jacqueline's pace in miles/minute = 1/0.16 miles/minute = 6.25 minutes/mile.
Answer: what math work
Step-by-step explanation:
Answer:
Step-by-step explanation:
There are 2 very distinct and important things that we need to know before completing the problem. First is that we are given that the cos of an angle is 1/3 (adjacent/hypotenuse) and it is in the first quadrant. We also need to know that the identity for sin2θ = 2sinθcosθ.
We already know cos θ = 1/3, so we need now find the sin θ. The sin ratio is the side opposite the angle over the hypotenuse, and the side we are missing is the side opposite the angle (we do not need to know the angle; it's irrelevant). Set up a right triangle in the first quadrant and label the base with a 1 (because the base is the side adjacent to the angle), and the hypotenuse with a 3. Find the third side using Pythagorean's Theorem:
which simplifies to
and
so
so that's the missing side. Now we can easily determine that

Now we have everything we need to fill in the identity for sin2θ:
and multiply all of that together to get

I don’t understand your question
360 seconds ..
6 times 60=360