Answer:
option C 13.5%
Step-by-step explanation:
As the heights of adults is normally distributed with mean=69 and standard deviation=2.5 so, the percent of men that are between 64 and 66.5 inches tall can be calculated as
P(64<X<66.5)=P[ (64-69)/2.5<(X-μ)/σ<(66.5-69)/2.5]
P(64<X<66.5)=P(-2<Z<-1)
P(64<X<66.5)=P(-2<Z<0)-P(-1<Z<0)
P(64<X<66.5)=0.4772-0.3413=0.1359
Thus, the percent of men are between 64 and 66.5 inches tall is 13.59%.
If we round the resultant quantity then it will be rounded to 13.6% but considering the given options, option C is most appropriate.
