So 5/8 inches to milimeters
we know that 1 in=2.54 cm so
5/8 in times 2.54= 1.5875 cm
1 cm=10 mm
1.5875 cm times 10=15.875mm aprox 16 mm, but best to go smaller since it won't fit if bigger
answer: 16mm (my recomendation would be 15mm)
Answer:
See the image below:)
Step-by-step explanation:
Answer:
it would be x =11*49
Step-by-step explanation:
Answer:
0.74 to 6.06
Step-by-step explanation:
The groups are independnet,
SE(xh bar-xa bar)=sqrt [sh^2/nh+sa^2/na]=sqrt [10.1^2/80+10.3^2/80]=1.61
At df=157, the t critical is 1.65
90%c.i=(xh bar-xa bar)+-tcritical SE(xh bar-xa bar)
=(25.2-21.8)+-1.65*1.61
=0.74 to 6.06
Answer:
3/1 or 3
Step-by-step explanation:
It rises up three and to the side one