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spayn [35]
3 years ago
11

5 is what percent of 23

Mathematics
1 answer:
Eddi Din [679]3 years ago
8 0
5 = what percent of 23

5 = x% of 23

5 = (x/100)*23

5 = 23x/100

5*100 = 23x

23x = 5*100

x = 5*100/23

x = 21.739

5 is ≈ 21.739% of 23 
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Joel and two friends went to the movies. They each spent $5.50 on a medium popcorn and also had to buy a ticket. Altogether, the
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8 0
3 years ago
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PLEASE HELP I WILL MARK THE BRAINLIEST
-BARSIC- [3]

Given: lines l and m are parallel, and line t is a transversal.

angle pair result/justification

1 and 2 are equal (vertical angles)

6 and 8 are equal (corresponding angles)

1 and 4 are equal (alternate exterior angles)

4 and 8 are supplementary angles (i.e. add up to 180 degrees, a straight angle)

Note:

alternate angles are on opposite sides of the transversal, and each attached to a different (parallel) line.

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8 0
3 years ago
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Pls help
KATRIN_1 [288]

Answer:

169.04 in² (nearest hundredth)

Step-by-step explanation:

Surface area of a cone = \pir² + \pirl

(where r = radius of the base and l = slant height)

Given slant height l = 10 and surface area = 188.5

Surface area  = \pir² + \pirl

188.5 = \pir² + 10\pir

\pir² + 10\pir - 188.5 = 0

r = \frac{-10\pi +\sqrt{(10\pi )^2-(4\times\pi \times-188.5)} }{2\pi } = 4.219621117...

Volume of a cone = (1/3)\pir²h

(where r = radius of the base and h = height)

We need to find an expression for h in terms of l using Pythagoras' Theorem a² + b² = c², where a = radius, b = height and c = slant height

r² + h² = l²

h² = l² - r²

h = √(l² - r²)

Therefore, substituting found expression for h:

volume of a cone = (1/3)\pir²√(l² - r²)

Given slant height l = 10 and r = 4.219621117...

volume = 169.0431969... = 169.04 in² (nearest hundredth)

5 0
2 years ago
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