<u>Answer:</u> The concentration of
in three significant figures will be 0.899 mol/L.
<u>Explanation:</u>
For the given reaction:

The above reaction follows zero order kinetics. The rate law equation for zero order follows:
![k=\frac{1}{t}([A_o]-[A])](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B1%7D%7Bt%7D%28%5BA_o%5D-%5BA%5D%29)
where,
k = rate constant for the reaction = 
t = time taken = 10 sec
= initial concentration of the reactant = 0.962 mol/L
[A] = concentration of reactant after some time = ?
Putting values in above equation, we get:
![6.28\times 10^{-3}=\frac{1}{10}(0.962-[A])](https://tex.z-dn.net/?f=6.28%5Ctimes%2010%5E%7B-3%7D%3D%5Cfrac%7B1%7D%7B10%7D%280.962-%5BA%5D%29)
![[A]=0.899mol/L](https://tex.z-dn.net/?f=%5BA%5D%3D0.899mol%2FL)
Hence, the concentration of
in three significant figures will be 0.899 mol/L.
Answer: the theory that all matter us made up of tiny invisible particles. Hope that help you out :)
Explanation:
Answer:
+2.5
Explanation:
So the oxidation number of S in Na2S4O6is +2.5.
Answer:
1(a) N = 3
(b) N = 0
(c) N = 5
(d) N = -2
(2) Molecular formula for benzene is C6H6
Explanation:
1(a) N02 1-
N + (2×-2) = -1
N-4 = -1
N = -1+4 = 3
(b) N2
2(N) = 0
N = 0/2 = 0
(c) NO2Cl
N + ( 2×-2) + (-1) = 0
N - 4 - 1 = 0
N - 5 = 0
N = 0+5 = 5
(d) N2H4
2(N) + (4×1) = 0
2N + 4 = 0
2N = 0 - 4 = -4
N = -4/2 = -2
(2) Molcular mass of benzene = 78g/mole = (6×12g of carbon) + (6×1g of hydrogen) = 72+6 = 78g/mole
Therefore, molecular formula for benzene is C6H6
Answer:
<h3>D energy of motion</h3>
Explanation:
Kinetic energy is the energy present in mass in motion